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marishachu [46]

3 years ago

13

An oxygen deficit occurs

2 answers:

Serggg [28]3 years ago

6 0

There is an oxygen deficit when an oxygen intake exceeds its intake in the body. During strenuous exercise, oxygen deficits occur naturally. The body works to fill up oxygen levels during the so - called regeneration period, when the drill is responsible for oxygen deficits.

Stolb23 [73]3 years ago

4 0

A second definition comes from Work Place Testing: “Oxygen deficit exists when a body's consumption of oxygen exceeds its intake.” Oxygen deficit occurs naturally during strenuous exercise. When exercise triggers an oxygen deficit, the body will work to replenish oxygen levels during what is known as a recovery period.

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You have a mixture of substances with diifferent sized molecules. How could you seperate them?

Trava [24]

Distillation, Magnetism, Filtration, Crystallization, Extraction,

3 0

3 years ago

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Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s

tatyana61 [14]

Answer:

$Q_T=63313.5\ J$

Explanation:

Given:

temperature of skin, $T_s=34^{\circ}C$

initial temperature of steam vapour, $T_v=100^{\circ}C$

latent heat of steam, $L=2256\ J.g^{-1}$

mass of steam, $m=25\ g$

specific heat of water, $c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}$

final temperature, $T_f=34^{\circ}C$

<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

$Q=m.c.\Delta T$

<u>Now the total heat given by the steam to form water at the given conditions:</u>

$Q_T=Q_{Lv}+Q_w$ ..............................(1)

where:

$Q_{Lv}=$ latent heat given out by vapour to form water of 100°C

$Q_w=$ heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

$Q_T=m(L+c.\Delta T)$

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4 0

3 years ago

As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh

MrMuchimi

Answer: $37^{\circ}$ North of west

Explanation:

Given

40,000-ton luxury line traveling 20 knots towards west and

60,000 ton freighter traveling towards North with 10 knots

suppose v is the common velocity after collision

conserving momentum in west direction

$20\times 40,000=(20,000+60,000)v\cos \theta$

suppose the final velocity makes \theta angle with x axis

$v\cos \theta =10----1$

Conserving Momentum in North direction

$10\times 60,000=80,000\times v\sin\theta$

$v\sin \theta =\frac{15}{2}----2$

divide 1 and 2

$\tan \theta =\frac{3}{4}$

$\theta =37^{\circ}$

so search in the area $37^{\circ}$ North of west to find the ship

3 0

3 years ago

A jet taxiing down the runway receives word that it must return to the gate. The jet is traveling 37.6 m/s when the pilot receiv

IrinaVladis [17]

Answer:

7 m/s^2

Explanation:

Given that the jet is traveling 37.6 m/s when the pilot receives the message.

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V = U - at

Since the plane is going to stop, the final velocity V = zero.

And the acceleration will be negative

Substitute all the parameters into the formula

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5.37a = 37.6

Make a the subject of formula

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Maurinko [17]

Answer:

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Explanation:

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