Question

Find the 63rd term of the arithmetic sequence 17, 26, 35

Answer 1

Answer:

a₆₃ = 575

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 17 and d = a₂ - a₁ = 26 - 17 = 9 , then

a₆₃ = 17 + (62 × 9) = 17 + 558 = 575