


and with that template in mind,
notice from a parent function of f(x) = x³,
a derived function with f(x+5) = (x + 5)³
has a C component of 5, C = 5, which means is the as the parent, just shifted to the left by 5 units.
Answer:
I am not sure
Step-by-step explanation:
I think if you look through and keep waiting for answers you'll eventually get it
Answer: 20
Step-by-step explanation:
numbers belonging to the figure on the left are 2.5 times less than on the right so to find x multiply 8 by 2.5 and that is 20
Answer:
The dimension of box=
Step-by-step explanation:
We are given that
Volume of box=4 cubic feet
Let x be the side of square base and h be the height of box
Volume of box=


Now, surface area of box,A=








Substitute x=2

Hence, the area of box is minimum at x=2
Therefore, side of square base,x=2 ft
Height of box,h=
Hence, the dimension of box=
Answer:
Step-by-step explanation:
The teacher has 7/8 pounds of clay given.
gives out 1/16 per station
7/8= 0.875 pound
7/8 / 1/16 pound= 14 maximum stations
14 stations divided by 2 classes = 7 in each room