Question

Find the roots of the quadratic equation :

Answer 1

• $\sf {x}^{2} + x + 2 = 0$

• $\sf{x}^{2} - 2x + x - 2 = 0$

• $\sf \: x(x + 2) - 1(x + 2) = 0$

• $\sf \: (x - 1)(x + 2) = 0$

• $\sf \: x - 1 = 0 \: \: \: \: \: \: \: \: \: x + 2 = 0$

• $\boxed{ \sf \: x = 1 \: \: \: \: \: \: x = - 2}$

$\sf{ \large \underline {Hope \: \: It's \: \: Welps \: \: uhh}}$

Answer 2

Answer:

Step-by-step explanation:

x = (-b ± √ (b² - 4ac) )/2a.