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3 years ago

Quadrilateral BCDE is a square. What is mZDCF?

Mathematics

1 answer:

o-na [289]3 years ago

7 0

Answer:

4 squares make up a triangle so divide the degrees if the square by the triangle.

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Use the graph to fill in the blank with the correct number.<br><br> f(0) = ________

Keith_Richards [23]

Answer:

55 square feet jsjjjis the answer

6 0

3 years ago

PLEASEEEEE HELPPPPPPPP

Ierofanga [76]

Answer:

2 and 4 has no soulotions, and C has one

Step-by-step explanation:

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2 years ago

Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten. The rest were either ripe or unripe. There were 18 more ripe oranges

Natalka [10]

Answer:

13:8:7

Step-by-step explanation:

84 - 24 = 60

60 oranges were either ripe or unripe.

18 more ripe oranges than unripe oranges.

x + 18 = ripe oranges

x = unripe oranges

x + 18 + x = 60

2x + 18 = 60

2x = 42

x = 21

21 are unripe oranges

21 + 18 = 39

39 oranges are ripe.

Ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.

39:24:21

13:8:7

4 0

3 years ago

Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2

NNADVOKAT [17]

$y'-\dfrac13y=\dfrac13xe^x\ln x\,y^{-2}$

Divide both sides by $\dfrac13y^{-2}(x)$ :

$3y^2y'-y^3=xe^x\ln x$

Substitute $v(x)=y(x)^3$ , so that $v'(x)=3y(x)^2y'(x)$ .

$v'-v=xe^x\ln x$

Multiply both sides by $e^{-x}$ :

$e^{-x}v'-e^{-x}v=x\ln x$

The left side can be condensed into the derivative of a product.

$(e^{-x}v)'=x\ln x$

Integrate both sides to get

$e^{-x}v=\dfrac12x^2\ln x-\dfrac14x^2+C$

Solve for $v(x)$ :

$v=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

Solve for $y(x)$ :

$y^3=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

$\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}$

4 0

3 years ago

In a power the -------------is an number used as the repeated factor

Butoxors [25]

The base. Hope this helps!

7 0

3 years ago