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ryzh [129]
2 years ago
9

Darren got 45 out of the 60 questions correct on a test. What percent of the questions did he get correct?

Mathematics
1 answer:
Arisa [49]2 years ago
6 0

Answer: To to find the percentage, you simply need to divide 45 by 60:

Step-by-step explanation:

45/60= .75

Move the decimal from the .75 over 2 times which would get you 75% on his test. So he got a 75%

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If x is a negative number, which of the following could equal the absolute value of x? Select all that apply. 3 5 0 -3
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It will be a number > 0.

so 3 and 5.
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3 years ago
What roles did militias play in the American Revolution? Your answer:
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Hey there! I'm happy to help!

A militia is a local army. During the Battle of Lexington and Concord, the local militia (called minutemen), the militia outnumbered the British at Concord and chased them all the way back to Boston. The militia aided in many American victories during the Revolutionary War.

I hope that this helps! Have a wonderful day! :D

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A mechanic estimates that a tire still has
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B

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6 0
2 years ago
if Dakota earned $15.75 in interest in account A and $28.00 in interest in account B after 21 months. if the simple interest rat
NISA [10]

keeping in mind that 21 months is more than a year, since there are 12 months in a year,  then 21 months is really 21/12 years.


\bf ~~~~~~ \stackrel{\textit{account A}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &15.75\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 15.75=P(0.03)\left( \frac{7}{4} \right)\implies \cfrac{15.75}{(0.03)\left( \frac{7}{4} \right)}=P\implies \boxed{300=P}


\bf ~~~~~~ \stackrel{\textit{account B}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &28\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 28=P(0.049)\left( \frac{7}{4} \right)\implies \cfrac{28}{(0.049)\left( \frac{7}{4} \right)}=P\implies \boxed{326.53\approx P}


so, clearly, you can see who's greater.

3 0
3 years ago
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