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katrin2010 [14]
2 years ago
8

Please help, I don’t really understand how to do this at all.

Mathematics
2 answers:
Alisiya [41]2 years ago
5 0

Answer:

i don't know exactly.

Step-by-step explanation:

but the might be an angle tool online.

Pepsi [2]2 years ago
5 0

Answer:

ML = 8.76, LK = 3.56

Step-by-step explanation:

Angle M = 24° is given and Angle K is marked to show it's a right angle. That's 90°. You filled in Angle L = 66° which is correct (subtract 180 - 24 - 90 = 66)

Now for the sides you need trigonometry. It's totally do-able! Let's do ML first. ML is the HYPOTENUSE (longest side and opposite from the right angle) and you're given MK = 8. MK is right next to Angle M, like it is literally apart of Angle M. That means that MK is an ADJACENT side to Angle M. The trig function that puts together ADJ and HYP is cosine. You do need a calculator or maybe your program has a drop down calculator.

cos 24° = ADJ/HYP

cos 24° = 8/ML

(ML)cos 24° = (8/ML)(ML)

(ML)cos 24° = 8

Divide both sides by cos24°

ML = 8/cos24° approximately= 8.76

Make sure sure your calculator is in "degree" mode. You will usually see a tiny "deg" on the scene or check on the "mode" key

You can use trig again to get the third side or use Pythagorean theorem.

Here is the trig. LK is OPPOSITE from angle M. If we use the MK again, the ADJACENT side, we'll need tangent.

tan 24° = LK/8

8tan24° = LK

3.56 = LK

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Ms Thomas drove at a constant rate for 45. She drove 39 miles during that time. If distance is determined by the equation d=rt w
Cerrena [4.2K]

Answer:

Ms. Thomas was driving at constant rate of 52 miles/hour.

Step-by-step explanation:

Given:

Total time to travel (t) = 45 minutes

Distance drove (d) = 39 miles

we need to find the constant rate in miles per hour at which she was driving.

Solution:

Now we know that;

We need to find constant rate at miles per hour;

But time is given in minutes.

So we will convert minutes into hour by dividing by 60 we get;

time t =\frac{45}{60}= 0.75\ hrs

Now we know that;

Distance is equal to rate times time.

framing in equation form we get;

distance d =rt

Or

rate r= \frac{d}{t} = \frac{39}{0.75}= 52 \ mi/hr

Hence Ms. Thomas was driving at constant rate of 52 miles/hour.

6 0
3 years ago
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

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V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

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Answer:

<h2>\frac{6}{25}</h2>

Step-by-step explanation:

<h3>\frac{3}{5} ÷ \frac{5}{2} = \frac{3}{5} ÷ \frac{2}{5} = \frac{6}{25}</h3>
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Answer:

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Step-by-step explanation:

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