1. The domain of a sqrt(x) is x > 0. So, L > 0.
2. The range of a S(x) = sqrt(x) is S(x) > 0 for all valid x > 0.
Answer:
The correct answer is "rational" . It is not an "integer" because it is a "decimal value". It is not "irrational" because the decimal value terminates and does not repeat.
