What is the electric field strength at a distance of .50 m from a 1.00x10^-6 c charge?
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Do not forget that mass = <span>volume x density
</span>Mass of 1 cm^3 = Density[/tex]
Then eventually we can find <span>mass of 5 cm^3 : =
</span>
So the answer is D
<span>And that's it. I'm sure it will help.</span>
</span>Mass of 1 cm^3 = Density[/tex]
Then eventually we can find <span>mass of 5 cm^3 : =
</span>
So the answer is D
<span>And that's it. I'm sure it will help.</span>
The distance traveled by the wood after the bullet emerges is 0.16 m.
The given parameters;
- <em>mass of the bullet, m = 23 g = 0.023 g</em>
- <em>speed of the bullet, u = 230 m/s</em>
- <em>mass of the wood, m = 2 kg</em>
- <em>final speed of the bullet, v = 170 m/s</em>
- <em>coefficient of friction, μ = 0.15</em>
The final velocity of the wood after the bullet hits is calculated as follows;
The acceleration of the wood is calculated as follows;
The distance traveled by the wood after the bullet emerges is calculated as follows;
Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.
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