Answer:
Explanation:
A ) weight of air + weight of tank = 013.5 + 3.2
= 16.7 kg
volume of air
= 3.2 / 1.225 = 2.61 m³
= volume of water displaced = 2.61 m³
weight of water displaced = 2.61 x 1025
= 2675.25 kg
buoyant force = 2675.25 kg
buoyant force = weight of displaced sea water
= volume of displaced sea water x density
= 15.7 x 10⁻³ x 1025
= 16.0925 kg
net force = buoyant force - weight
= 2675.25 - 16.7
= 2658.55 kg
B ) net force will be in downward direction as weight is higher .
C ) weight of tank + weight of water in it
= 13.5 + 15.7 x 10⁻³ x 1025
= 13.5 + 16.0925
= 29.5925 kg
buoyant force = 16.0925 kg
net force = 29.5925 - 16.0925
= 13.5 kg
D ) net force down wards
Answer:
The momentum of the two-block system is 18 kg-m/s
Explanation:
It is given that,
Mass of block A, 
Mass of block B, 
Velocity of block A, 
Velocity of block B, 
(it is moving in opposite direction)
We need to find the momentum of two block system. It is given by the product of mass and velocity for both blocks i.e.
p = -18 kg-m/s
So, the momentum of two block system is 18 kg-m/s. Hence, this is the required solution.
Answer:
a)0.48 m/s
b) 0.583 m/s
Explanation:
As the wagon rolls,
momentum'p'= m x v => 95.8 x 0.530 = 50.774 Kgm/s
(a)Rock is thrown forward,
momentum of rock = 0.325 x 15.1 = 4.9075 Kgm/s
Conservation of momentum says momentum of wagon is given by
50.774 - 4.9075 = 45.8665
Therefore, Speed of wagon = 45.8665 / (95.8-0.325) = 0.48 m/s
(b) Rock is thrown backward,
momentum of wagon = 50.774 + 4.9075 = 55.68 Kgm/s
Therefore, speed of wagon = 55.68 / (95.8-0.325) = 0.583 m/s
Answer:
Density can be decreased by increasing the volume and keeping the mass same .
Answer:
Explanation:
t=Time airborne=2.54 s
R= horizontal range= 25.5 m
From the projectile motion equations we know that:
H=7.9 m
