Answer:
Work done = -220,000 Joules. 
Explanation:
<u>Given the following data;</u>
Mass = 1100kg
Initial velocity = 20m/s
To find workdone, we would calculate the kinetic energy possessed by the car. 
Kinetic energy can be defined as an energy possessed by an object or body due to its motion. 
Mathematically, kinetic energy is given by the formula;

Where,
- K.E represents kinetic energy measured in Joules. 
- M represents mass measured in kilograms. 
- V represents velocity measured in metres per seconds square. 
Substituting into the equation, we have;
 
 
 
 
K.E = 220,000J
Therefore, the workdone to bring the car to rest would be -220,000 Joules because the braking force is working to oppose the motion of the car. 
 
        
             
        
        
        
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
   KE1  = KE2
The kinetic energy of the system before the collision is solved below.
  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s. 
        
             
        
        
        
Answer:
x = 1.6 + 1.7 t^2      omitting signs
a) at t = 0     x = 1.6 m
b) V = d x / d t = 3.4 t
at t = 0     V = 0
c) A = d^2 x / d t^2 = 3.4     (at t = 0  A = 3.4 m/s^2)
d)  x = 1.6 + 1.7 * (4.4)^2 = 34.5    (position at 4.4 sec = 34.5 m)
 
        
             
        
        
        
The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5