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coldgirl [10]
3 years ago
7

The angular quantities: angular displacement, angular velocity, angular acceleration, are defined in a very similar way to the l

inear quantities. The angular displacement represents the angle through which an object has rotated (the difference between two angular positions). The angular velocity equals the angular displacement divided by the elapsed time. The angular acceleration equals the change in the angular velocity divided by the elapsed time. Suppose an object travels through an angular displacement, Δθ, of 50.9 rad over a time of 4.10 s. What is the average angular velocity, ω?
Physics
1 answer:
Lena [83]3 years ago
4 0

Answer: [tex]12.415 rad.s^{-1}[/tex]

Explanation: Angular velocity is the rate of change in angular displacement.

We know that:

Angular velocity,      \omega= \frac{\Delta \theta}{t}....................(1)

where:

  • t= time
  • \Delta \theta = angular displacement in radians

<u>Given that:</u>

  • t = 4.10 s
  • Δθ = 50.9 radian

Putting the respective values in eq. (1)

\omega = \frac{50.9}{4.10}

\omega = 12.415 rad.s^{-1}

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25=c^2

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Question 20 (4 points)
irinina [24]

Explanation:

C is correct.

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So

250 = 50(a)

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2 years ago
What are the four types of musical instruments and what are the physical behind each type of musical instrument
pishuonlain [190]

Answer:

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Explanation:

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8 0
3 years ago
A positive charge is placed in an electric field that points west. What direction is the force on the positive particle? I think
Kisachek [45]
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3 0
4 years ago
A billiards ball B rests on a horizontal surface and is struck by another billiards ball A of the same mass m = 0.2 kg. Ball A i
SOVA2 [1]

Answer:

v1 = 15.90 m/s

v2 = 8.46 m/s

mechanical energy before collision = 32.4 J

mechanical energy after collision = 32.433 J

Explanation:

given data

mass m = 0.2 kg

speed = 18 m/s

angle =  28°

to find out

final velocity and  mechanical energy both before and after the collision

solution

we know that conservation of momentum remain same so in x direction

mv = mv1 cosθ + mv2cosθ

put here value

0.2(18) = 0.2 v1 cos(28) + 0.2 v2 cos(90-28)

3.6 =  0.1765 V1 + 0.09389 v2    ................1

and

in y axis

mv = mv1 sinθ - mv2sinθ

0 = 0.2 v1 sin28 - 0.2 v2 sin(90-28)

0 = 0.09389 v1 - 0.1768 v2   .......................2

from equation 1 and 2

v1 = 15.90 m/s

v2 = 8.46 m/s

so

mechanical energy  before collision = 1/2 mv1² + 1/2 mv2²

mechanical energy before collision = 1/2 (0.2)(18)² + 0

mechanical energy before collision = 32.4 J

and

mechanical energy after collision = 1/2 (0.2)(15.90)² + 1/2 (0.2)(8.46)²

mechanical energy after collision = 32.433 J

7 0
3 years ago
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