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3 years ago

How does the electric force between two charged objects change when the

Physics

1 answer:

castortr0y [4]3 years ago

3 0

Answer:

When the electric force between two charged objects change, the distance between the objects increases in Iicreasing the separation distance between objects and decreases the force of attraction or repulsion between objects.

Hope it helps.

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Which of the following is not a reason fluorescent lamps are advantages over incandescent lamps?

iren2701 [21]

It’s because flourecent lights operate at higher temperatures than incadecent lights.

3 0

3 years ago

A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?

prohojiy [21]

Answer:

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

8 0

3 years ago

How long will it take a person walking at 3.2 m/s to travel 16 m? *

BigorU [14]

Answer:

speed=distance/time

time=distance/speed

time=16/3.2

time=5 seconds

time will take 5 seconds

3 0

3 years ago

A musician on a unicycle is riding at a steady 6.2 m/s while playing their well tuned oboe at an A above middle C (440 Hz). They

Verizon [17]

Answer:

The frequency of the beat is $f_t = 8Hz$

Explanation:

From the question we are told that

The speed of the ride $v = 6,2 m/s$

The frequency of the oboe is $f = 440Hz$

The temperature outside is $T = 27^oC$

Generally the speed of sound generated in air is mathematically evaluated as

$v_s = 331 + 0.61 T$

Substituting value

$v_s = 331 + 0.61 *27$

$v_s = 347.47 \ m/s$

The frequency of sound(generated by the musician on he park) getting to the musicians on the unicycle is mathematically evaluated as

$f_a = \frac{v_s }{v_s - v} f$

substituting values

$f_a = \frac{347.47 }{347.47 - 6.2} * 440$

$f_a = 448Hz$

Since the musician on the park is not moving the frequency of sound (from the musicians riding the unicycle )getting to him is = 440Hz

The beat frequency these musician here is mathematically evaluated as

$f_t = f_a - f$

So $f_t = 448 - 440$

$f_t = 8Hz$

3 0

3 years ago

Every 10 seconds a pendulum makes 2 cycles. What are the period and frequency of this pendulum

jek_recluse [69]

(10 seconds) / (2 cycles) = (10/2) (sec/cycle) = 5 seconds.

That's the pendulum's period.

Frequency = 1 / (period) = 1/5 per second = 0.2 Hz.

5 0

3 years ago