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3 years ago

If we rotate on our axis does that count as a day

1 answer:

s2008m [1.1K]3 years ago

5 0

Yes if we rotate on our axis one full time it is considered a day. but if we go around the entire sun one full time it is considered a year. hope this helps

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Assume that the car at point A and the one at point E are traveling along circular paths that have the same radius. If the car a

vazorg [7]

Answer:

The magnitude of car A acceleration is 4 times that of car E

Explanation:

Assuming they are traveling at a constant speed. Their (centripetal) acceleration is as the following

$a = \frac{v^2}{r}$

where v is the (linear) velocity and r is the radius. We can use this to calculate their ratio

$a_A / a_E = \frac{v_A^2/r_A}{v_E^2/r_E} = \left(\frac{v_A}{v_E}\right)^2\frac{r_E}{e_A}$

Since $v_A = 2V_E \rightarrow \frac{v_A}{v_E} = 2$ and $r_A = r_E$

$a_A / a_E = 2^2 = 4$

So the magnitude of car A acceleration is 4 times that of car E

6 0

3 years ago

Bill forgets to put his car in park and it starts rolling west. When it is moving at a speed of 3.5 m/s, it collides with Tanya'

djverab [1.8K]

PART A)

momentum of Bill's car

mass = 900 kg

speed = 3.5 m/s towards west

so momentum of this car given as

$P_1 = 900(3.5) = 3150 kg m/s$

Similarly momentum of Tanya's car

mass = 1100 kg

speed = 2 m/s towards East

so momentum will be

$P_2 = 1100(2) = 2200 kg m/s$

Total momentum of both cars will be

$P = 3150 -2200 = 950 kg m/s$ Towards west

PART B)

Since there is no external force on the system of two cars

So here total momentum of both cars will remains conserved

So final momentum of two cars will be same as initial momentum

$P = 950 kg m/s$ towards west

Part C)

final momentum of Bills car

$P_1 = (900)(2) = 1800 kg m/s$ Towards East

now we have

$P_1 + P_2 = 950$

$1100 v - 1800 = 950$

$v = 2.5 m/s$ towards west

3 0

3 years ago

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Question 3.Two forces are acting on a 30-kg object, 200 N up and 300 N

atroni [7]

Answer:

It is 3 m/s² downward.

Explanation:

The mass of an object, m = 30 kg

Upward force, F = 200 N

Downward force, F' = -300 N

We need to find the magnitude and direction of its acceleration.

Net force = F+F'

= 200+(-300)

= -100 N

We know that,

Force, F = ma, a is acceleration of the object

$a=\dfrac{F}{m}\\\\a=\dfrac{-100}{30}\\\\a=-3.33\ m/s^2\approx -3\ m/s^2$

Hence, the acceleration is -3 m/s² and it is acting in the downward direction.

4 0

2 years ago

Batteries can supply a steady flow of electrons.<br> True<br> False

Alecsey [184]

The answer is TRUE, batteries CAN supply a steady flow of electrons.

6 0

3 years ago

The collective body of observations of a natural phenomenon on which scientific explanations are based is called?

zhenek [66]

Experimental Evidence.

Scientists conduct experiments or observations to gather evidence that either support or disprove a given hypothesis. Hence, all the scientific explanations are based on this body of observations.

4 0

3 years ago

Read 2 more answers