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Harman [31]
2 years ago
10

A parallelogram has a height of x cm. The length of its base is 4 cm greater than its height. A triangle has the same height as

the parallelogram. The length of the triangle’s base is 20cm.
What is the value when the triangle and the parallelogram have the same area?
Mathematics
1 answer:
LuckyWell [14K]2 years ago
4 0

The value of x when the triangle and the parallelogram have the same area is 6 units

<h3>The dimensions</h3>

The dimension of the parallelogram is given as:

  • Height = x
  • Base = 4 + x

The dimension of the triangle is given as:

  • Height = x
  • Base = 20

<h3>Areas</h3>

The area of a shape is the amount of space it occupies

The area of the parallelogram is calculated as:

Area = x (4 + x)

The area of the triangle is calculated as:

Area = 0.5 \times 20 \times x

Area = 10x

Both areas are equal.

So, we have:

x(4 + x) = 10x

Divide both sides by x

4 + x = 10

Subtract 4 from both sides

x =6

Hence, the value of x is 6 units

Read more about areas at:

brainly.com/question/2126265

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Bumek [7]

Answer:

The value of (x + y)³ is 1728.

Step-by-step explanation:

First, you have to find the value of x + y :

x² + 2xy + y² = 144

x² + xy + xy + y² = 144

x(x + y) + y(x + y) = 144

(x + y)(x + y) = 144

(x + y)² = 144

x + y = √144

x + y = 12

Next, the value of (x + y)³ :

(x + y) = 12³ = 1728

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Step-by-step explanation:

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The function g(x) = 12,500(0.91)x represents the value of a piece of farm equipment after x years. Approximately when will its v
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Answer:

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Step-by-step explanation:

The question is wrong. The correct function is :

g(x)=12500(0.91)^{x}

We have the function g(x) that represents the value of a piece of farm equipment after x years.

This means that when x=0 its original value is :

g(0)=12500(0.91)^{0}=12500

Now we want to calculate approximately when will its value be half its original value. Then, we write :

\frac{12500}{2}=6250

6250 is half of its original value. We need to find x that satisfies the following equation :

g(x)=6250=12500(0.91)^{x}

Solving for x :

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0.5=(0.91)^{x}

Now we apply natural logarithm to each side of the equation :

ln(0.5)=ln[(0.91)^{x}]

Using logarithm properties :

ln(0.5)=ln[(0.91)^{x}] ⇒

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x=\frac{ln(0.5)}{ln(0.91)} ⇒

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The correct option is B. 7.3 years

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