X²+2xy+y²=144, (x+y)³?

Mathematics

2 answers:

Bumek [7]3 years ago

5 0

Answer:

The value of (x + y)³ is 1728.

Step-by-step explanation:

First, you have to find the value of x + y :

x² + 2xy + y² = 144

x² + xy + xy + y² = 144

x(x + y) + y(x + y) = 144

(x + y)(x + y) = 144

(x + y)² = 144

x + y = √144

x + y = 12

Next, the value of (x + y)³ :

(x + y) = 12³ = 1728

Phantasy [73]3 years ago

4 0

Answer:

(x+y)³=1728

Step-by-step explanation:

(x+y)²=144=12²

(x+y)³=12*12*12=1728

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Among a large group of patients recovering from shoulder injuries, it is found that 22% Visit both a physical therapist and a ch

EastWind [94]

Answer:

0.48

Step-by-step explanation:

First of all. let's recall probability formula needed for solving the problem.

We know that, If the events A and B are not mutually exclusive, the probability is:

<em>probability of event (A or B) = probability of event A + probability of event B – p(A and B). </em>

This formula will be used in calculations of this problem.

Let's consider that event A is patient visiting physical therapist; event B is patient visiting chiropractor.

P (A∩B) = 0.22 (visiting both physical therapist and chiropractor) ⇔ p(A and B)

P(B) = P(A) + 0.14 [ Probability patient visiting chiropractor is 0.14 more than probability visiting physical therapist]

Patients visiting none of these is 12%

Those who visit either therapist or chiropractor are amount to 1 - 0.12 = 0.88

Now we should use the formula mentioned in the beginning of the text:

0.88 = P(A) + P(B) - 0.22 ⇒ P(A) + P(B) = 1.1

If we replace P(B) by P(A) + 0.14 ⇒ 2P(A) + 0.14 = 1.1 ⇒ 2P(A) = 1.1 - 0.14 = 0.96

So, P(A) = 0.96/2 = 0.48 [Probability of patients visiting therapist]

7 0

3 years ago

Find what the question asks. 200 points. Will mark brainleist

kotegsom [21]

Note:
The area of a circle with radius r is πr².
An entire circle has a central angle of 360°.

For the sector with radius = (3+4) = 7cm and a central angle of 120°, the area is
$A_{1}= \frac{120}{360}*(49 \pi ) = \frac{49}{3} \pi \, cm^{2}$

For the sector with radius = 3 cm and a central angle of 120°. the area is
$A_{2}= \frac{120}{360} *(9 \pi ) = 3 \pi \, cm^{2}$

The area of the shaded sector (see the figure) is
$A=A_{1}-A_{2} = ( \frac{49}{3} -3) \pi = \frac{40}{3} \pi \, cm^{2}$

Answer: $\frac{40}{3} \pi \, cm^{2}$