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GaryK [48]
3 years ago
15

This is very important

Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0
1. 1650 / 55 = 330 / 11 = 30
2. 5634 / 18 = 939 / 3 = 313
3. 6440 / 28 = 920 / 4 = 230
4. 5256 / 52 = 2628 / 26 = 1314 / 13 = 101.07
5. 1955 / 85 = 391 / 17 = 23
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How to integrate 1/(1-y)^2
Akimi4 [234]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/866966

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy}\\\\\\ =\mathsf{\displaystyle\int\!\dfrac{-1}{(1-y)^2}\cdot (-1)\,dy}\\\\\\ =\mathsf{\displaystyle- \int\!(1-y)^{-2}\cdot (-1)\,dy\qquad\quad(i)}


Substitution:

\begin{array}{lcl} \mathsf{1-y=u}&\quad\Rightarrow\quad&\mathsf{y=1-u}\\\\ &&\mathsf{dy=-1\,du} \end{array}


So the integral \mathsf{(i)} becomes

=\mathsf{\displaystyle -\int\! u^{-2}\,du}\\\\\\ =\mathsf{-\,\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\ =\mathsf{-\,\dfrac{u^{-1}}{-1}+C}\\\\\\ =\mathsf{u^{-1}+C}\\\\\\ =\mathsf{\dfrac{1}{u}+C}

=\mathsf{\dfrac{1}{1-y}+C}\\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy=\dfrac{1}{1-y}+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral fraction rational substitution power differential calculus</em>

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3 years ago
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Step-by-step explanation:

The first inquiry has 12 ways

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gladu [14]

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You pay $10 to play the following game of chance. there is a bag containing 12 balls: three are red, five are green, and the res
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$ -2.08  expected to lose  

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