Answer:
A) ![{MnO_4}^- + 3 H^+ + \frac{5}{2} H_2O_2 \rightarrow Mn^{2+} + 4 H_2O + \frac{5}{2} O_2](https://tex.z-dn.net/?f=%7BMnO_4%7D%5E-%20%2B%203%20H%5E%2B%20%2B%20%5Cfrac%7B5%7D%7B2%7D%20H_2O_2%20%5Crightarrow%20Mn%5E%7B2%2B%7D%20%2B%204%20H_2O%20%2B%20%5Cfrac%7B5%7D%7B2%7D%20O_2%20)
B) 7.5 molar
Explanation:
A) <u>Reduction</u>
![{MnO_4}^- + 8 H^+ + 5e^- \rightarrow Mn^{2+} + 4 H_2O](https://tex.z-dn.net/?f=%7BMnO_4%7D%5E-%20%2B%208%20H%5E%2B%20%2B%205e%5E-%20%5Crightarrow%20Mn%5E%7B2%2B%7D%20%2B%204%20H_2O)
<u>Oxidation</u>
![H_2O_2 \rightarrow O_2 + 2 H^+ + 2e^-](https://tex.z-dn.net/?f=H_2O_2%20%5Crightarrow%20O_2%20%2B%202%20H%5E%2B%20%2B%202e%5E-)
Multiplying the oxidation reaction by 5/2 and adding it to the reduction equation:
![{MnO_4}^- + 8 H^+ + 5e^- \rightarrow Mn^{2+} + 4 H_2O](https://tex.z-dn.net/?f=%7BMnO_4%7D%5E-%20%2B%208%20H%5E%2B%20%2B%205e%5E-%20%5Crightarrow%20Mn%5E%7B2%2B%7D%20%2B%204%20H_2O)
+
![\frac{5}{2} H_2O_2 \rightarrow \frac{5}{2} O_2 + 5 H^+ + 5e^-](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20H_2O_2%20%5Crightarrow%20%5Cfrac%7B5%7D%7B2%7D%20O_2%20%2B%205%20H%5E%2B%20%2B%205e%5E-)
-----------------------------------------------------------------------------------------------------
![{MnO_4}^- + 3 H^+ + \frac{5}{2} H_2O_2 \rightarrow Mn^{2+} + 4 H_2O + \frac{5}{2} O_2](https://tex.z-dn.net/?f=%7BMnO_4%7D%5E-%20%2B%203%20H%5E%2B%20%2B%20%5Cfrac%7B5%7D%7B2%7D%20H_2O_2%20%5Crightarrow%20Mn%5E%7B2%2B%7D%20%2B%204%20H_2O%20%2B%20%5Cfrac%7B5%7D%7B2%7D%20O_2%20)
B) 10 ml = 0.01 L
20 ml = 0.02 L
mol of MnO4− = molarity*volume = 1.5*0.02 = 0.03
1 mol of MnO4− reacts with 5/2 mol of H2O2, then:
mol of H2O2 = 0.03*5/2 = 0.075
molarity = mol/volume = 0.075/0.01 = 7.5 molar
Answer:
<h3>The answer is 0.79 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
![density = \frac{mass}{volume} \\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C)
From the question
mass = 2.56 g
volume = 3.25 mL
We have
![density = \frac{2.56}{3.25} \\ = 0.78769230...](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7B2.56%7D%7B3.25%7D%20%20%5C%5C%20%20%3D%200.78769230...)
We have the final answer as
<h3>0.79 g/mL</h3>
Hope this helps you
Sodium metal explodes on contact with water so probably a combustion reaction
Answer:
Explanation:
Most blood types are determined by red cell antigens that differ by one or two amino acids, the Rh positive blood group contains the D antigen
I hope this was helpful, please mark as brainliest
Answer:
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