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UkoKoshka [18]
3 years ago
12

0 / 5 pts Question 3 In the reaction of aluminum with iron III oxide, if you start with 54.2 grams of aluminum, how many grams o

f iron III oxide are needed for the reaction to occur?​
Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0
Could you please mark me as brainliest?

Answer: 160.40 g Fe2O3 are needed.

Explanation:

Balanced equation: 2 Al + Fe2O3 —> Al2O3 + 2Fe

54.2 g Al * 1 mol Al / 26.98 g Al * 1 mol Fe2O3 / 2 mol Al * 159.69 g Fe2O3 / 1 mol = 160.40 g Fe2O3 are needed.
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We are given the pOH of the solution of 10.75. pOH is the property of the solution that is related to the OH ion concentration of the solution. THe formula to be followed is pOH = -log (OH); OH- = 10^-pOH. In this case, OH-  = 10^-10.75 equal to B. 1.778 x 10^-11 M
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3 years ago
Explain that : how we explore different between Licl and Nacl
Leona [35]

Answer:

See the explanation below, please.

Explanation:

In the bunsen burner, the gas and air inlet can be regulated manually. In the case of metals (such as lithium and sodium in this case) they contain an electron in the latter in its external electronic configuration. They are characterized by transferring electrons easily and produce the emission of light when excited, producing flames of different colors in the lighter (orange for sodium and red / scarlet for lithium)

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3 years ago
What is the half-life of 20 g of a radioactive sample if 5 g remain after 8 minutes?
Anni [7]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 20 g

m (final mass after time T) = 5 g

x (number of periods elapsed) = ?

P (Half-life) = ? (in minutes)

T (Elapsed time for sample reduction) = 8 minutes

Let's find the number of periods elapsed (x), let us see:

m =  \dfrac{m_o}{2^x}

5 =  \dfrac{20}{2^x}

2^x = \dfrac{20}{5}

2^x = 4

2^x = 2^2

\boxed{x = 2}


Now, let's find the half-life (P) of the radioactive sample, let's see:

T = x*P

8 = 2*P

2\:P = 8

P = \dfrac{8}{2}

\boxed{\boxed{P = 4\:minutes}}\Longleftarrow(Half-Life)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

5 0
3 years ago
What forces are important in the creation of magma?
kherson [118]
"the factors that mainly affect in the formation of magma can be summarized into three: temperature, pressure, and composition"

I hope this helps =^._.^=
4 0
3 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

                                     = B g

Amount of NaOCl in this stock solution = 5% of B g

                                     = \frac{5}{100} x B g

                                     = 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

                        = 0.005 g

B = \frac{0.005}{0.05}

  = 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0
3 years ago
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