Explanation:
The given reaction will be as follows.
So, equilibrium constant for this equation will be as follows.
![K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D%5BH_%7B2%7D%5D%5E%7B2%7D%7D)
As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.
= 
= 0.173
Thus, we can conclude that equilibrium constant for the given reaction is 0.173.
<span>A similar thing occurred with the circles as did with the electroscope. When we initially brought the charged pole close to, the bar pulled in the circle since it was of polarization. At that point, once the bar touched the circle, the pole repulsed the circle. This is on the grounds that once the pole and circle touched, the electrons exchanged thus did the protons, consequently leaving the circle with a positive net charge. The nearer the bar is to the circle the more it repulsed, however, it didn't influence the charge of the circle once the circle was touched by the pole.</span>
Answer:
<h2> ncjchchdgshdihdyshfjgjfjfjfjfjfjfjcjfjfjcn jivk kvi</h2>
Kinetic energy is the energy possessed by an object due to its motion. If an object is moving, then it has kinetic energy. If an object has kinetic energy, then it is moving. Many students confuse kinetic energy with potential energy.
