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Crank
2 years ago
6

Determine the smallest integer value of x in the solution of the following inequality.

Mathematics
2 answers:
kykrilka [37]2 years ago
6 0

Answer:

x>\frac{-22}{3}

Step-by-step explanation:

Let's solve your inequality step-by-step.

3x+4>−18

Step 1: Subtract 4 from both sides.

3x+4−4>−18−4

3x>−22

Step 2: Divide both sides by 3.

3x

3

>

−22

3

x>

−22

3

blondinia [14]2 years ago
5 0

Answer:

x> -7\frac{1}{3}

Step-by-step explanation:

3x+4> -18

1. We need to get rid of +4 by minusing 4 from both sides.  

3x>-22

2. Isolate x by dividing both sides by 3

x>-22/3

3. -22/3 can be turned into a mixed number

The answer is x> -7\frac{1}{3}

Hope this helps :)

Have a nice day!

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3 years ago
Which expression is equivalent to n2 + 26n + 88 for all values of n?
Lelechka [254]

Answer:

Option B is correct.

The expression which is equivalent to  n^2+26n+88  is; (n+22)(n+4)

Explanation:

Given the equation: n^2+26n+88 for all values of n.

The quadratic equation in this form; ax^2+bx+c =0

First find two numbers that multiply to give ac and add to give b.

From the given equation;

a =1 , b = 26 and c =88

then,

the two number that multiply to give ac =88 is, 22 or 4

and they add up to give b=26 (i.e 22+4)

Now, rewrite the middle term i.e 26n with 22n and 4n , we have

n^2+22n+4n+88=0

Now, factor the first two terms and last two terms,

n(n+22)+4(n+22)

we see that (n+22) is common to both terms so, we have;

(n+22)(n+4)

Therefore, the expression (n+22)(n+4) is equivalent to  n^2+26n+88

Check:

(n+4)(n+22) = n\cdot n+ 22n+4n+88=n^2+26n+88   [ True]



5 0
3 years ago
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