Determine the smallest integer value of x in the solution of the following inequality.

Mathematics

2 answers:

kykrilka [37]2 years ago

6 0

Answer:

$x>\frac{-22}{3}$

Step-by-step explanation:

Let's solve your inequality step-by-step.

3x+4>−18

Step 1: Subtract 4 from both sides.

3x+4−4>−18−4

3x>−22

Step 2: Divide both sides by 3.

−22

blondinia [14]2 years ago

5 0

Answer:

$x> -7\frac{1}{3}$

Step-by-step explanation:

3x+4> -18

1. We need to get rid of +4 by minusing 4 from both sides.

3x>-22

2. Isolate x by dividing both sides by 3

x>-22/3

3. -22/3 can be turned into a mixed number

The answer is $x> -7\frac{1}{3}$

Hope this helps :)

Have a nice day!

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Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of

Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

$\triangle ABC \sim \triangle NMP$