When taking square roots, you can't take square roots of negative roots of negative numbers. So, what will work for the domain of u(x) is what makes u(x) zero or more. We can make an inequality for that.
u(x) ≥ 0.

9x + 27 ≥ 0 by squaring both sides
9x ≥ -27
x ≥ -3
So the domain of the function is when x ≥ -3 is true.
Y - 0.32y = (1 - 0.32)y = 0.68y
What ? What ?
Did you write the first two answers in pencil ?
They're correct ! Just do the other two exactly the same way.
-- Do the division problem printed in the "Distance ..." column.
-- Multiply the answer by 0.1 .
-- Write the new answer in the last column.
Step-by-step explanation:
9x² + 6 = 12x
3x² + 2 = 4x
3x² − 4x + 2 = 0
Use quadratic formula.
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-4) ± √((-4)² − 4(3)(2)) ] / 2(3)
x = [ 4 ± √(16 − 24) ] / 6
x = [ 4 ± √(-8) ] / 6
x = (4 ± 2i√2) / 6
x = (2 ± i√2) / 3
15% of 40
Of = Multiplication
15% Multiply by 40
Set up a equation
15/100= x/140
Cross Multiply
15* 140= 100*x
2100= 100x
Divide both sides by 100x
2100/100x= 100x/100x
X= 21