Answer:
I don't see how the three existing points could ever become a square with the addition of a foiurth point.
Step-by-step explanation:
See the attached image.
A square would require that all angles be 90 degrees. The given points are the top three points on the graph. If we enter the two equations that intersect these points (blue and black lines), we can see that the angle on top is not 90 degrees. I can't see that this could ever be a square with a fourth point, z. I did find a value for z that make the four points a parallelogram.
40/100 simplify that and you will get .4.
Step-by-step explanation:
let the big cube side be b
small cube side be s
s = 2/3 * b
bv + sv = 118.125
b^3 + 8/9 b^3= 118.125
17 b^3/8 = 118.125
b^3 = 55.58
b = 3.816in
s = 2.544in
Find the domain of the function f(x)=2/3x+3 . The given range is -3,0,5,9. A.1,3,19/3,9 b.-4,-2,4/3,4 c.-9,9/2,,3,9 d.0,9/2,12,1
algol13
Answer:
I believe it is C?
Step-by-step explanation: