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Annette [7]
3 years ago
13

How do I Rewrite the function by completing the square x^2+8x-29

Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:

  (x +4)^2 -45

Step-by-step explanation:

The square of a binomial has the form ...

  (x +a)^2 = x^2 +2ax +a^2

That is, the constant term (a^2) is the square of half the coefficient of the linear term: (2a/2)^2 = a^2.

To "complete the square", you add 0 in the form of the desired constant added to its opposite. Here, we want the constant for the square to be (8/2)^2 = 16. So, we can add 0 = 16 -16 to the expression:

  x^2 +8x +16 -29 -16

  (x^2 +8x +16) -45 . . . . group the terms that make the square

  (x +4)^2 -45 . . . . rewritten after completing the square

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SIMPLE INTEREST
cupoosta [38]
The answer would be 5 years. I=PxRxT.
3 0
3 years ago
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Jenny goes to the store with $9.87. She then spends $2.81 of it. How much money does she have left?​
Blababa [14]

Answer:

Step-by-step explanation:

$9.87

- <u>2.81</u>

$7.06 Jenny has left

4 0
3 years ago
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1.How many solutions does the system have?
MaRussiya [10]

Answer:

c. infinitely many solutions

Step-by-step explanation:

5 0
3 years ago
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If triangle RST is within Quadrant 2 and csc T = 13/12, what is the value of cotT?
zhuklara [117]

Answer:

\boxed {cot T = -\frac{5}{12}}

Step-by-step explanation:

<u>Finding the missing side</u> :

  • x² = 13² - 12²
  • x² = 169 - 144
  • x = √25
  • x = 5

<u>Taking the cot value</u> :

  • cot T = adjacent / opposite
  • cot T = -5/12 (As cot is negative in Quadrant 2)
5 0
2 years ago
Read 2 more answers
Cargo ships arrive at a loading dock at a rate of 2 per day. The dock has the capability of handling 3 arrivals per day. How man
Vsevolod [243]

Answer:

4 days

Step-by-step explanation:

We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.

P(x>3 cargo ships) = 1-P(x<=3)

P(x>3) = 1-P(x<=3)

P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]

P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]

P(x>3) = 1- [0.1353(1+2+2+1.33)]

P(x>3) = 1-0.856

P(x>3) = 0.1431

Als n=30, expected number is

E(x) =30*P(x>3)

E(x) = 30*0.1431

E(x) = 4.293

I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships

6 0
3 years ago
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