1 mole of nitric acid produce 1 mole of ammonium nitrate.
moles in 5000 kg of ammonium nitrate :
( molecular mass of ammonium nitrate is 80 gm/mol )
So, number of moles of nitric acid required are also 62500 moles.
Mass of 62500 moles of nitric acid :
Hence, this is the required solution.
Answer:
6CO2 + 6H20 ----> C6H12O6 + 6O2
Explanation:
(Carbon Dioxide) + (Water) ------> (Glucose) + (Oxygen)