Answer:
Explanation:
For the growth and flourishing of animals Aromatic amino acids are very important, but because of lack of shikimate these amino acids are not synthesized in animals pathway.But this pathway is found in both plants and micro organisms and they have the ability to produce these amino acids as well as some secondary metabolites required in animals.
There are different role played by this pathway in organisms such as;
1) It serve as a source of Tryptophan and phenylalanie which are important aromatic amino acid.
2)Neuroactive substances such as serotonin,epinephrine are biosynthesized as result of the product from the pathway.
3)Alkaloids that's found in plants as well as antibiotics possessed by microbes, which are essential therapeutical in animals are secondary metabolites that is biosynthesized as a result of the activities of this product of this pathway.
4)Shikimate is useful in the synthesizing of 6-Fluoroshikimic acid.
5) The shikimate pathway is important for the synthesis of a plethora of aromatic compounds in both plants and bacteria as well as fungi.
An isotope is the vary of neutrons in an element, causing its atomic mass to change. While an ion is a charged atom that bonds to be stable.
CH and O is the reactants while CO and H2O is the products
Answer:
B. materials change their properties.
Explanation:
In a chemical change, materials often change their properties because a re-arrangement of atoms takes place.
A chemical change is one in which new kind of matter is formed.
It is always accompanied by energy changes.
- Chemical changes are not reversible.
- They lead to the production of new kinds of matter
- It involves mass changes
- Requires considerable amount of energy
To solve this problem, we must assume ideal gas behaviour so
that we can use Graham’s law:
vA / vB = sqrt (MW_B / MW_A)
where,
<span>vA = speed of diffusion of A (HBR)</span>
vB = speed of diffusion of B (unknown)
MW_B = molecular weight of B (unkown)
MW_A = molar weight of HBr = 80.91 amu
We know from the given that:
vA / vB = 1 / 1.49
So,
1/1.49 = sqrt (MW_B / 80.91)
MW_B = 36.44 g/mol
Since this unknown is also hydrogen halide, therefore this
must be in the form of HX.
HX = 36.44 g/mol , therefore:
x = 35.44 g/mol
From the Periodic Table, Chlorine (Cl) has a molar mass of
35.44 g/mol. Therefore the hydrogen halide is:
HCl
