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marishachu [46]

3 years ago

12

Dee's clothing is having a discount of 40% on all shirts. Let x represent the regular price of any shirt in the store. Write an

expression that can be used to find the sale price of any shirt in the store.

1 answer:

Elis [28]3 years ago

4 0

Y=0.40x because the sale which is 40% off would be on x amount of shirts

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Which transformation on the coordinate plane is a dilation?

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Answer:

It is the third one

Step-by-step explanation:

if that was the question even, I chose this as dilation is basically just getting bigger or smaller but without rotation,sliding, and none of the sides should be changing

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Joseph write the number pattern below 100; 101, 96; 97; 92; 93, 88; 89; what is the next pattern?

sergij07 [2.7K]

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multiples of 8

Step-by-step explanation:

79 80. 82. 81. 83 84 85 86. 88. 87. 89 90. 92. 91. 93 94 95 96. 98. 97. 99 100 ... 101. 3. (a) Write down the first 8 multiples of 8. (b) Write down the first 8 multiples of 6. ... (d) What are the next two numbers that are multiples of both 6 and 8? 4.

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3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

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Read 2 more answers

Help me please...........:)

BabaBlast [244]

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Step-by-step explanation:

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