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3 years ago

Which graph below shows the correct solution to the following inequality? x≥5

Mathematics

1 answer:

GuDViN [60]3 years ago

4 0

The correct answer would have to be a

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Solve the following system of equations.

krek1111 [17]

The answer is B.

The attached file is how I got the answer.

Hope this helped :)

5 0

3 years ago

Use suitable Identities and find <br>●( X - 5 ) ( x-5 )<br>●( 3x +2 ) (3x -2 )<br>●( 1+x )(1+x)

Nonamiya [84]

Answer:

$.$

Step-by-step explanation:

<h2><u>IdEnTiTy UsED</u></h2>

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$(x - 5)(x - 5)$

=(x-5)²

$(3x - 2)(3x + 2)$

${(3 x)}^{2} - {(2)}^{2}$

$= 9 {x}^{2} - 4$

$(1+x)(1+x)$

= (1+x)²

6 0

4 years ago

A stock-car race lasted 2.07 hours. how many seconds did the race last?

kolezko [41]

$2.07 hr x \frac{60 min}{1 hr} x \frac{60 sec}{1 min} = 7452 sec$

8 0

3 years ago

Solve: 16x = 8<br> A. 1/2<br> B. 2<br> C. 4<br> D. 12

Rudik [331]

X=1/2
Hope this helped! :3

3 0

3 years ago

Read 2 more answers

Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac

Anestetic [448]

Answer:

Tacoma's population in 2014 will be 587,439 people

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by the formula

$y=a(1+r)^x$

where

y is Tacoma's population in thousand

x is the number of years since 2000

r is the rate of change

a is the initial value

we have

$a=200\\r=8\%=8/100=0.08$

substitute

$y=200(1+0.08)^x$

$y=200(1.08)^x$

what will Tacoma's population be in 2014?

Find the value of x

$x=2014-2000=14\ years$

substitute the value of x

$y=200(1.08)^{14}=587.439\ thousand$

therefore

Tacoma's population in 2014 will be 587,439 people

5 0

3 years ago