Question

Two go carts, A and B race eachother around a 1.0 km track. Go cart A travels at a constant speed of 20.0 m/s. Go cart B accelerates uniformly from rest at a rate of 0.333 m/s 2. Which go cart wins the rice and by how much time?

Answer 1

We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec

Therefore

The Cart A wins the Race and by 25.5( 77.7-50)secs

From the question we are told

• Two go carts, A and B race each other around a 1.0 km track.
• Go cart A travels at a constant speed of 20.0 m/s.
• Go cart B accelerates uniformly from rest at a rate of 0.333 m/s

For Cart A

Generally the equation for the Velocity  is mathematically given as

$v=\frac{d}{t}\\\\t=\frac{d}{v}\\\\t=\frac{1000}{20}\\\\t=50sec$

For Cart B

Generally the Newtons equation for the Motion  is mathematically given as

$S=ut+1/2at^2\\\\Therefore\\\\S=ut+1/2at^2\\\\1000=0+1/2*(0.33)t^2\\\\t=\frac{1000}{1/2*(0.33}}\\\\t=77.5secs$

Since

Cart A spends t=77.5secs and Cart B spends t=50sec

Therefore

The Cart A wins the Race and by 25.5( 77.7-50)secs

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