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4vir4ik [10]
3 years ago
8

A transformer is to be used to provide power for a computer disk drive that needs 6.4 V (rms) instead of the 120 V (rms) from th

e wall outlet. The number of turns in the primary is 405, and it delivers 500 mA (the secondary current) at an output voltage of 6.4 V (rms). Find the current in the primary.
Physics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

The current in the primary is 0.026 A

Explanation:

Using the formula

I1 = (V1/V2)*I2

we have

I1 = (6.4/120)*0.500

I1 = 0.026 A

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Answer:

80 degress is needed to boil 200g of water from 30 degress

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A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.75 m/s. If the roof is pitched at
dalvyx [7]

Answer:

a) t = 0.528 s

b) D = 1.62 m

Explanation:

given,

speed of the baseball = 3.75 m/s

angle made with the horizontal = 35°

height of the roof edge = 2.5 m

using equation of motion

s = ut +\dfrac{1}{2}gt^2

2.5 = vsin\theta \ t +\dfrac{1}{2}gt^2

2.5 = 3.75\ sin35^0 \ t +\dfrac{1}{2}\times 9.8 t^2

4.9 t² + 2.15 t - 2.5 = 0

on solving the above equation

t = 0.528 s

b) D = v cos θ × t

D = 3.75 × cos 35° ×0.528

D = 1.62 m

3 0
3 years ago
Witch of the following best describes the forms of electromagnetic waves produced by sunlight ?
zubka84 [21]

Answer:

A: Sunlight contains ultraviolet waves only.

Explanation:

Hopefully this helps!

6 0
2 years ago
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Question
lana [24]
26,000 years is approximately how long it takes for the earths revolution to change
3 0
3 years ago
Water flows on the inside of a steel pipe with an ID of 2.5 cm. The wall thickness is 2 mm, and the convection coefficient on th
Hatshy [7]

Answer:

U = 11.67 W/m² °C

Explanation:

Inner diameter, d = 2.5 cm = 0.025 m

Thickness of the wall, t = 2 mm = 0.002 m

thus, the outer diameter, D = d + 2t = 0.025 + 2 x 0.002 = 0.029 m

h_i =500 W/m^2.^oC

h_0 =12 W/m^2.^oC

Now, based on outside convection heat transfer

we have

\frac{1}{UA_o}=\frac{1}{h_iA_i}+\frac{1}{h_oA_o}

on rearranging, we get

\frac{1}{U}=\frac{1}{h_i}\frac{A_o}{A_i}+\frac{1}{h_o}

where, A_i\ \textup{and}\ A_o are the perimeter respective to inner and and outer diameter

on substituting the values, we get

\frac{1}{U}=\frac{1}{500}\frac{0.029^2}{0.025}+\frac{1}{12}

or

U = 11.67 W/m² °C

6 0
3 years ago
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