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4vir4ik [10]
3 years ago
8

A transformer is to be used to provide power for a computer disk drive that needs 6.4 V (rms) instead of the 120 V (rms) from th

e wall outlet. The number of turns in the primary is 405, and it delivers 500 mA (the secondary current) at an output voltage of 6.4 V (rms). Find the current in the primary.
Physics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

The current in the primary is 0.026 A

Explanation:

Using the formula

I1 = (V1/V2)*I2

we have

I1 = (6.4/120)*0.500

I1 = 0.026 A

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A square current-carrying loop is placed in a uniform magnetic field B with the plane of the loop parallel to the magnetic field
Radda [10]

Answer:

(A) a net torque but no net force on the loop.

Explanation:

The total force on the loop is zero because the forces on the opposite sides of the loop are equal but act in opposite directions and as a result they cancel each other out. The two forces on opposite sides to the axis of rotation each give rise to a torque about the axis of rotation. This torque is directed along the axis of rotation.

5 0
3 years ago
What percentage of the takeoff velocity did the plane gain when it reached the midpoint of the runway? a plane accelerates from
ElenaW [278]
When is at the end of the runway the velocity of the plane is given by the equation vf^{2}=0+2*a*s    where s=1800 m is the runway length. Thus
vf^{2}=2*5*1800=18000 (m/s)^{2}      
vf =134.164 (m/s)  

At half runway the velocity of the plane is
v^{2}=2*5* \frac{1800}{2}=9000 ( \frac{m}{s} )^{2}
 
v= \sqrt{9000}=94.87 ( \frac{m}{s})

Therefore at midpoint of runway the percentage of takeoff velocity is
‰P= \frac{v}{vf}=  \frac{94.87}{134.164}=0.707
6 0
3 years ago
A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
3 years ago
A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.
4vir4ik [10]
The photon can be absorbed and the energy of the photon is exactly equal to the energy-level difference between the ground state and the level d.

8 0
3 years ago
A car is running at a velocity of 50 miles/hour and the driver accelerates the car by 10miles/hour.How far the car travels from
dezoksy [38]
Initial velocity u = 50 miles/hour
acceleration a = 10 miles/hour
Time t = 2 hours
Distance travelled S = ut + (at^2)/2
Substituting the values in the second equation of motion,
S = 50*2 + (10 * 2 *2)/2
S = 100 + 20
S = 120 miles
Therefore the distance travelled by the car in the next two hours is 120 miles
4 0
3 years ago
Read 2 more answers
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