Answer:
12345678910
Step-by-step explanation:
TANQR
Answer:
The actual value is -181/20. Estimate could be -200/20
Step-by-step explanation:
9514 1404 393
Answer:
M₅ = 1.6570
Step-by-step explanation:
The basic idea is to find the function values at x ∈ {1.1, 1.3, 1.5, 1.7, 1.9}, add those values, and multiply the result by 1/5. Those x-values are the midpoints of intervals 0.2 units wide, between x = 1 and x = 2. The width 0.2 is the total interval width (2-1=1) divided by n = 5.
The calculation and results are shown in the attachment. Rounded to 4 decimal places, the integral is ...
M₅ = 1.6570
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The actual integral is about 1.6574, so this is pretty close.
Answer:
Tanks of 15.3081 gallons and larger are considered too large.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

How large does a tank have to be to be considered too large
largest 2%, so at least the 98th percentile.
The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.




Tanks of 15.3081 gallons and larger are considered too large.
Answer:
3
Step-by-step explanation:
All factorials 5 and above are evenly divisible by 15, so have no remainder. Thus, you are interested in ...
mod(1! +2! +3! +4!, 15) = mod(1 +2 +6 +24, 15)
= mod(33, 15) = 3
The remainder is 3.