The given question is incomplete. The complete question is ;
A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.
Answer: The molarity is 0.81 M and molality is 0.82 m
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,
n= moles of solute
= volume of solution in ml = 200 ml

Now put all the given values in the formula of molarity, we get

Thus molarity is 0.81 M
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

where,
n = moles of solute
= weight of solvent in g

Mass of solution = 
mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g
Now put all the given values in the formula of molality, we get

Therefore, the molality of solution is 0.82m
Answer is:<span>increase [Cl</span>₂<span>] and remove HCl from the product.
</span>Chemical reaction: Cl₂ + CH₂Cl₂ → CHCl₃(chloroform) + HCl.
According to Le Chatelier's Principle, the position of
equilibrium moves to counteract the change, the position of equilibrium
will move so that the concentration of reactants decrease (Cl₂) and concentration of
products of chemical reaction increase (CHCl₃) if increase concentration of reactants and decrease concentration of products.
Answer:
4.10x10⁻³g.
4.10 mg.
Explanation:
Hello,
In this case, considering the given number, we can see it has two digits after the first nonzero digit that is four (4) which is also at the third decimal place, it means that the scientific notation has a negative power as it is at the left of the given zeros, therefore it is:
4.10x10⁻³g.
Moreover, since the proper prefix for the factor x10⁻³ is milli, the number with prefix is:
4.10 mg.
Best regards.
The answer to your question is D. Sound waves travel faster in more dense material, and the more dense the material the louder the sound is.
Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g