For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol
<h3>What is the result in a buffer ph of 4. 01?</h3>
Generally, the equation for the pH is mathematically given as
pH=pKa+logsalt/acid
Generally, the equation for the Chemical Reaction is mathematically given as
HCl+CH3CooNa---->NaCl+CH3OOH
Therefore
4.01=4.74+log\frac{0.8-x}{1.3+x}
-0.52=log\frac{0.8-x}{1.3+x}
x=0.313mol
In conclusion, The moles of HCl required is
x=0.313mol
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