Answer:
The particles of the medium just vibrate in place.
Explanation:
As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on. Particles of the medium don't actually travel along with the wave.
The number of mole sulphuric acid in each mL of solution is 0.0183 mol/mL.
<h3>What is concentration?</h3>
- Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.
- Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.
- Any type of chemical mixture can be referred to by the term "concentration," however solutes and solvents in solutions are most usually mentioned.
- There are different types of molar (quantity) concentration, including normal concentration and osmotic concentration.
<h3>How is concentration determined?</h3>
- Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V.
- To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.
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A B C these are the answers hopes this help <3
B protons are positive atoms and are inside the nucleus
Answer:
Explanation:
The chemical equation is:
There are several definitions of acid and bases: Arrhenius', Bronsted-Lowry's and Lewis'.
Bronsted-Lowry model defines and <em>acid</em> as a donor of protons, H⁺.
In the given equation HNO₃ is such substance: it releases an donates its hdyrogen to form the H₃O⁺ ion.
On the other hand, a <em>base</em> is a substance that accepts protons.
In the reaction shown, H₂O accepts the proton from HNO₃ to form H₃O⁺.
Thus, H₂O is a base.
In turn, on the reactant sides the substances can be classified as acids or bases.
H₃O⁺ contain an hydrogen that can be donated and form H₂O; thus, it is an acid (the conjugated acid), and NO₃⁻ can accept a proton to form HNO₃; thus it is a base (the conjugated base).
