Answer:
$1.50 per pound
Step-by-step explanation:
$6 for 4 lb
$6 / 4
since wanting to figure out how much 1 lb cost then divide the total by 4 since $6 is 4 lb
6 / 4 = 1.5
hope this helps
Answer:
I think c
Step-by-step explanation:
i might be wrong so dont trust my answer but i would've picked C
3x + 17 - 5x = 12 - (6x+3)
4x + 17 = 9
4x = -8
X = -2
Answer:
(a) ![-65](https://tex.z-dn.net/?f=-65)
(b) ![-65](https://tex.z-dn.net/?f=-65)
Step-by-step explanation:
We have been a function
. We are asked to find the instantaneous rate of change of the function and the slope of the tangent line at point
.
(a) First of all, we will find the derivative of our given function using product rule.
![(f\cdot g)'=f'\cdot g+f\cdot g'](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%27%3Df%27%5Ccdot%20g%2Bf%5Ccdot%20g%27)
![y'=\frac{d}{dx}(x^3-3)\cdot (x^2-5x+1)+(x^3-3)\cdot \frac{d}{dx}(x^2-5x+1)](https://tex.z-dn.net/?f=y%27%3D%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E3-3%29%5Ccdot%20%28x%5E2-5x%2B1%29%2B%28x%5E3-3%29%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2-5x%2B1%29)
![y'=3x^2\cdot (x^2-5x+1)+(x^3-3)\cdot 2x-5](https://tex.z-dn.net/?f=y%27%3D3x%5E2%5Ccdot%20%28x%5E2-5x%2B1%29%2B%28x%5E3-3%29%5Ccdot%202x-5)
![y'=3x^4-15x^3+3x^2+2x^4-6x-5x^3+15](https://tex.z-dn.net/?f=y%27%3D3x%5E4-15x%5E3%2B3x%5E2%2B2x%5E4-6x-5x%5E3%2B15)
![y'=5x^4-20x^3+3x^2-6x+15](https://tex.z-dn.net/?f=y%27%3D5x%5E4-20x%5E3%2B3x%5E2-6x%2B15)
Now, we will substitute
in our derivative function to find slope of tangent line as:
![y'=5(2)^4-20(2)^3+3(2)^2-6(2)+15](https://tex.z-dn.net/?f=y%27%3D5%282%29%5E4-20%282%29%5E3%2B3%282%29%5E2-6%282%29%2B15)
![y'=5(16)-20(8)+3(4)-12+15](https://tex.z-dn.net/?f=y%27%3D5%2816%29-20%288%29%2B3%284%29-12%2B15)
![y'=80-160+12-12+15](https://tex.z-dn.net/?f=y%27%3D80-160%2B12-12%2B15)
![y'=-65](https://tex.z-dn.net/?f=y%27%3D-65)
Therefore, the slope of the tangent line is -65 at point
.
(b) We know that instantaneous rate of change of the function at a point is equal to the derivative of the function at that point.
We already figured it out that derivative of our given function at
is
, therefore, the instantaneous rate of change of the function is also
at point
.
The answer is 4!!!!!!!!!!!!!!!!!!!!!!!!!!!!