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3 years ago

Andrew is half his brother's age. Three years ago, the sum of their ages was 24. How old are they each now? Please answer Fast.

Mathematics

1 answer:

Viktor [21]3 years ago

5 0

Answer:

Andrew 10 and his brother 20 years old

Step-by-step explanation:

three years ago

7 and 17 add up to 24

Hope this helps

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Which linear inequality is represented by the graph?

Romashka [77]

Answer:

1/3 is the slope and if it’s less than or greater to that, then the bottom half of the graph is shaded in.

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3 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

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3 years ago

How do you find the neutron of an atom?

EleoNora [17]

Neutrons are in the nucleus with the protons.
If you need more help text me :) hope it helps

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3 years ago

The highest common factor of 98 and 42

ohaa [14]

Answer:14

Step-by-step explanation:Start by writing like this below

98 =2×7×7

42 =2×3×7

H.C.F=2×7

=14

Take the number which is common like in 98 and 42, (2) and (7) are common

and then multiply the two numbers.

Hope it helps you!

5 0

3 years ago

Read 2 more answers

PLEASE HELP ITS ALMOST DUE

taurus [48]

Answer:

we have"

$\frac{q}{36}=\frac{16-q}{28}\\\\28q=36(16-q)\\\\28q=576-36q\\\\64q=576\\\\=>q=9$

Step-by-step explanation:

6 0

3 years ago