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ANTONII [103]
3 years ago
11

What does Newton's second law of motion say

Physics
2 answers:
atroni [7]3 years ago
7 0

Answer:

Newton's Second law of motion: "Force = mass × acceleration."

Explanation:

An example of the second law of motion is when you are riding a bike. Your bike is the mass and our leg muscles pushing on the pedals of your bike are the force.

DIA [1.3K]3 years ago
5 0
Newton's second law of movement can be formally expressed as takes after: The increasing speed of a question as created by a net power is specifically relative to the size of the net power, in an indistinguishable bearing from the net power, and contrarily corresponding to the mass of the protest.
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Answer:position relative to the starting point

Explanation:

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Two planets are orbiting a star. Planet A is closer to the star than Planet B. Which description explains the expected motion of
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Eld a distance r1 from P. The second particle is then released. Determine its speed when it is a distance r2 from P. Let q = 3.1
zheka24 [161]

Answer:

v_{f}=1721.1m/s

Explanation:

Given data

q = 3.1 µC

m = 47 mg

r1 = 0.83 mm

r2 = 2.5 mm.

As we know that:

dK=-dU\\(1/2)mv_{f}^{2}-(1/2)mv_{i}^{2}=-(\frac{kq^{2} }{r_{f}}-\frac{kq^{2} }{r_{i}} )\\    (1/2)*(47*10^{-6}kg )v_{f}^{2}-(1/2)*(47*10^{-6}kg)(0)=-[(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{2.5*10^{-3}}-(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{0.83*10^{-3}} )]\\2.35*10^{-5} v_{f}^{2}=69.61\\v_{f}=\sqrt{\frac{69.61}{2.35*10^{-5}} }\\v_{f}=1721.1m/s

5 0
3 years ago
The color of an object we see is determined by the
aksik [14]

Answer:

An object appears white when it reflects all wavelengths and black when it absorbs them all. Red, green and blue are the additive primary colors of the color spectrum. Combining balanced amounts of red, green and blue lights also produces pure white.

Explanation:

7 0
3 years ago
A 70-cm-diameter wheel accelerates uniformly from 160rpm to 280rpm in 4.0s. Determine (a) its angular acceleration, and (b) the
poizon [28]

Explanation:

Given that,

Diameter of the wheel, d = 70 cm = 0.7 m

Initial angular speed, \omega_i=160\ rpm=16.75\ rad/s

Final angular speed, \omega_f=280\ rpm=29.32\ rad/s

Time, t = 4 s

(a) Angular acceleration,

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{29.32-16.75}{4}\\\\\alpha =3.14\ rad/s^2

(b) Tangential acceleration is :

a=r\alpha \\\\a=0.35\times 3.14\\\\a=1.085\ m/s^2  

Angular speed of the wheel after 2 seconds is :

\omega_f=\omega_i+\alpha t\\\\\omega_f=16.75+3.14\times 2\\\\\omega_f=23.03\ rad/s

Radial acceleration will be :

a=\omega_f^2r\\\\a=(23.03)^2\times 0.35\\\\a=185.6\ m/s^2

Hence, this is the required solution.

4 0
3 years ago
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