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3 years ago

HELP How many electrons can exist in the second shell surrounding an atomic nucleus?

Physics

2 answers:

shepuryov [24]3 years ago

6 0

Aaaaaaaaaaaaaaaaaaaaaa hope it helps

svet-max [94.6K]3 years ago

3 0

More than 8 <span> electrons can exist in the second shell surrounding an atomic nucleus.</span>

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An elastic conducting material is stretched into a circular loop of 9.65 cm radius. It is placed with its plane perpendicular to

Nadya [2.5K]

Answer:

The induced emf in the coil is 0.522 volts.

Explanation:

Given that,

Radius of the circular loop, r = 9.65 cm

It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.

The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , $\dfrac{dr}{dt}=-0.756\ m/s$

Due to the shrinking of radius of the loop, an emf induced in it. It is given by :

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V$

So, the induced emf in the coil is 0.522 volts.

8 0

2 years ago

Hurry

marishachu [46]

6x8 = 48 feet

you can jump 48 feet on the moon

6 0

2 years ago

You drop two balls of equal diameter from the same height at the same time. Ball 1 is made of metal and has a greater mass than

Lelechka [254]

Answer:

The drop time ball 1 is less than the drop time of ball 2. A further explanation is provided below.

Explanation:

The net force acting on the ball will be:

⇒ $F_{net}=mg-F_r$

Here,

F = Force

m = mass

g = acceleration

Now,

According to the Newton's 2nd law of motion, we get

⇒ $F_{net} = ma$

To find the value of "a", we have to substitute " $F_{net}=ma$ " in the above equation,

⇒ $ma=mg-F_r$

⇒ $a=g-\frac{F_r}{m}$

We can see that, the acceleration is greater for the greater mass of less for the lesser mass. Thus the above is the appropriate solution.

8 0

2 years ago

Read 2 more answers

The driving force for an electric current is called

qaws [65]

Its called electro motive force . let me know if its right

6 0

3 years ago

Read 2 more answers

Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direc

Lerok [7]

Answer:

424.26 m/s

Explanation:

Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q

The relative speed will be calculated by using pythagorean theorem

Relative speed = sqrt(300^2 + 300^2)

Relative speed = sqrt( 180000 )

Relative speed = 424.26 m/s

Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s

7 0

2 years ago