The valence electrons increase as you move left to right.
Answer:
B
Explanation:
Given:-
- The charge of the test particle q = 3.0 * 10^-9 C
- The force exerted by the metal sphere F = 6.0 * 10^-5 N
Find:-
The magnitude and direction of the electric field
strength at this location?
Solution:-
- The relationship between the electrostatic force F exerted by the metal sphere on the test-charge and the Electric Field strength E at the position of test charge is given by:
F = E*q
- Using the data given we can determine E:
E = F / q
E = (6.0 * 10^-5) / (3.0 * 10^-9)
E = 20,000 N/C
- The direction of electric field is given by the net charge of the source ( metal sphere). The metal sphere is negative charge hence the direction of Electric Field strength E is directed towards the metal sphere.
Answer:
t = 166 years
Explanation:
In order to calculate the amount of years that electrons take to cross the complete transmission line. You first calculate the drift speed of the electrons by using the following formula:
(1)
I: current on the wire = 1,010A
n: free charge density = 8.50*10^28 electrons/m^3
A: cross-sectional area of the transmission line = π*r^2
r: radius of the cross-sectional area = 2.00cm = 0.02m
You replace the values of the parameters in the equation (1):

Next, you use the following formula:
(2)
x: length of the line transmission = 310km = 310,000m
You replace the values of vd and x in the equation (2):

Finally, you convert the obtained t to seconds

The electrons take approximately 166 years to travel trough the complete transmission line
Answer:
APA and MLA are the two format sources.
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Answer:
440hz
Explanation:
saxophone a plays at 430hz and a frequency of 5 beats per second can be heard so saxophone b is playing at a frequency 10hz louder than saxophone A making it 440hz