Answer:A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of the ice block melted as a result of the work done by friction? (Latent Heat of water is 3.3*10^5J/kg)
Explanation:
Answer:
3.08 Nm
Explanation:
N = 200, diameter = 6 cm, radius = 3 cm, I = 7 A, B = 0.90 T, Angle = 30 degree
The angle made with the normal of the coil, theta = 90 - 30 = 60 degree
Torque = N I A B Sin Theta
Torque = 200 x 7 x 3.14 x 0.03 x 0.03 x 0.90 x Sin 60
Torque = 3.08 Nm