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timama [110]
3 years ago
5

Two equal masses are attached to separate identical springs next to one another. One mass is pulled so its spring stretches 20 c

m and the other is pulled so its spring stretches only 10 cm. The masses are released simultaneously.Which mass reaches the equilibrium point first?
Physics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

Both reaches equilibrium simultaneously.

Explanation:

Given that,

First stretch spring= 20 cm

Second stretch spring = 10 cm

Two equal masses are suspended from identical spring.

Their forces constants are equal time period for oscillation

Using formula of time period

T=2\pi\sqrt{\dfrac{m}{k}}

Where, T = time period

m = mass

k = spring constant

Time period independent of amplitude.

Hence, Both reaches equilibrium simultaneously.

vazorg [7]3 years ago
7 0

Answer:

both reaches at the same time.

Explanation:

The time period of the mass is given by

T=2\pi \sqrt{\frac{m}{K}}

where, K be the spring constant and m be the mass attached.

As both the masses are same and springs are identical so K is same for both the springs.

Thus, both the masses will reach at the equilibrium position at the same time.

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