Answer:
Both reaches equilibrium simultaneously.
Explanation:
Given that,
First stretch spring= 20 cm
Second stretch spring = 10 cm
Two equal masses are suspended from identical spring.
Their forces constants are equal time period for oscillation
Using formula of time period
Where, T = time period
m = mass
k = spring constant
Time period independent of amplitude.
Hence, Both reaches equilibrium simultaneously.
Answer:
both reaches at the same time.
Explanation:
The time period of the mass is given by
where, K be the spring constant and m be the mass attached.
As both the masses are same and springs are identical so K is same for both the springs.
Thus, both the masses will reach at the equilibrium position at the same time.
Answer:
a. The thickness of the wire is 2.5 mm.
b. The wire is 0.25 cm thick.
Explanation:
Number of turns of the wire = 10
The length of total turns = 25 mm
a. The thickness of the wire can be determined by;
thickness of the wire =
=
= 2.5 mm
Therefore, the wire is 2.5 mm thick.
b. To determine the thickness of the wire in centimetre;
10 mm = 1 cm
So that,
2.5 mm = x
x =
= 0.25 cm
The wire is 0.25 cm thick.
Answer:
122.84 J
Explanation:
Since plate is square, area, A is given by
The distance between plates, d, is given in the question as 2mm=0.002m
Charge on plate, Q, as given in the question is 240
Assuming mica dielectric constant, k of 7
Capacitance, C is given by
C=
Stored energy, E is given by
E=
Therefore, the stored energy is 122.84 J