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Artemon [7]
3 years ago
10

2. A sound wave in a steel rail has a frequency of 620 Hz and a wavelength of 10.5 m. What

Physics
2 answers:
Alex3 years ago
5 0

Answer:Speed of sound in steel is 6510m/s.

Explanation:

Speed, v= frequency,f÷ wavelength

v=?, f= 620, wavelength= 10.5

v= 620× 10.5

= 6510m/s

den301095 [7]3 years ago
5 0
V=f¥
=620x10.5
V=6510m/s
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3 years ago
A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 35.5 m/s. a) What is the coeff
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The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.

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Let the coefficient of friction between the roadway and the wheels of the truck be "μ".

As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.

The centripetal force acting on the truck is given as:

F_c=\frac{mv^2}{R}

Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.

Frictional force is given as:

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Therefore, frictional force, f=\mu mg

Now, frictional force = centripetal force

f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu = \frac{v^2}{Rg}

Plug in the given values and solve for 'μ'. This gives,

\mu=\frac{(35\ m/s)^2}{(150\ m)(9.8\ m/s^2)}\\\\\mu=\frac{1225\ m^2/s^2}{1470\ m^2/s^2}\\\\\mu=0.833

Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833

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