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zlopas [31]
3 years ago
13

The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)

It will be unchanged.c)It will be one-half of the original force.d)It will be cut to a fourth of the original force.
Physics
1 answer:
zzz [600]3 years ago
5 0

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

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Two cars are involved in a crash (no one was hurt in the accident). If
Lunna [17]
Im fairly certain that the answer would be D, and this is because of the law of conservation of energy/momentum.
8 0
3 years ago
A rock is thrown horizontally from a high building at 33.8 m/s. What is the magnitude of its velocity 4.25 s later?
Alex17521 [72]
<h2>Answer:53.63ms^{-2}</h2>

Explanation:

The equations of motion used in this question is v=u+at

When a object is projected horizontally from a sufficiently height,the x-component of acceleration remains zero because there is no force that drags the object in x direction.

But,due to gravity,the object accelerates downward at a rate of 9.8ms^{-2}.

In X-Direction,

Given that initial velocity=u_{x}=33.8ms^{-1}

Using v=u+at,

v_{x}=33.8+(0)4.25=33.8ms^{-1}

In Y-Direction,

Given that initial velocity=u_{x}=0ms^{-1}

Using v=u+at,

v_{y}=0+(9.8)4.25=41.65ms^{-1}

v=\sqrt{v_{x}^{2}+v_{y}^{2}}

v=\sqrt{1142.44+1734.72}=\sqrt{2877.163}=53.63ms^{-1}

7 0
4 years ago
A drag racing vehicle travels from 0 to 100mph north in 5 seconds. What is the acceleration
kap26 [50]

The acceleration of the car is 8.9 m/s^2

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Here we have to convert the initial and final velocity of the vehicle into SI units. So we have:

u = 0 is the initial velocity

v=100 mph \cdot \frac{1609 m/mi}{3600 s/h}=44.7 m/s is the final velocity

t = 5 s is the time elapsed

Solving for a, we find the acceleration:

a=\frac{44.7-0}{5}=8.9 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
4 years ago
When a car is traveling 120 km/h how many times more kinetic energy would it have than if it were
LekaFEV [45]

Answer: 9

Explanation:

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the speed (v) by which it moves i.e K.E = 1/2 x mass x velocity^2

So, car is traveling 120 km/h

KE = 1/2x m x (120 km/h)^2

KE = 0.5 x m x 14400

KE1 = 7200m

So, car is traveling 40 km/h

KE = 1/2x m x (40 km/h)^2

KE = 0.5 x m x 1600

KE2 = 800m

Now, divide the value of kinetic energy obtained during 120 km/h by that obtained during 40 km/h

i.e 7200m / 800m

= 9

Thus, the kinetic energy will be 9 times more at a speed of 120 km/h than at 40 km/h

4 0
3 years ago
When you swim in a pool, Select one: a. rolling friction occurs. b. fluid friction occurs. c. sliding friction occurs. d. static
Oduvanchick [21]

Answer:

b. fluid friction occurs

Explanation:

Water is a liquid and both going through air gas and liquid cause fluid friction.

5 0
3 years ago
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