Answer:
The initial speed of the ball was 26.2 m/s
Explanation:
When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:

we need to obtain the time taken to go down.

We have a horizontal displacement and the time taken to stop, so:

so:

The bowling ball is at rest, so it only has gravitational potential energy.
Ug = mgy
Ug = (2)(9.8)(40) = 784 J
Need any more help?
Question:
A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.
(a)60 (b)90 (c)120
Answer:
(a)5.42 N (b)6.26 N (c)5.42 N
Explanation:
From the question
Length of wire (L) = 2.80 m
Current in wire (I) = 5.20 A
Magnetic field (B) = 0.430 T
Angle are different in each part.
The magnetic force is given by

So from data

Now sub parts
(a)

(b)

(c)

<span> The
failure of the anchovy harvest in 1972 was blamed on El Niño.</span>
Answer:
The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1
Explanation:
Detailed explanation and calculation is shown in the image below