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Lilit [14]
3 years ago
11

Mickey had three substances. He hit each of them with a hammer. A red

Physics
1 answer:
Verizon [17]3 years ago
6 0

Answer:

A & D

Explanation:

:p

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How do objects with the same charger interact
maxonik [38]

The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other; and negatively charged objects and neutral objects attract each other.

7 0
3 years ago
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The radii of the sprocket assemblies and the wheel of the bicycle in the figure are:
Furkat [3]
To solve this task we have to make a proportion, but firstly we have to set up all the main points : so, the distance is  s=r(B), that has its <span>r=radius,B=angle in rad velocity v=ds/dt= w(r)
Do not forget about </span> w = angular speed in rad/s and w1 = 1 revolution/sec = 2Pi (rad/s)
Now we can go to proportion
v1=v2
w1*r1 = w2r2w2 = w1 * r1/r2 = 2w1 = 4Pi (rad/s)
w2 = w3 (which is the   angular velocity of the rear wheel) &#10;
SOLVING FOR A : v3 = w3 * r3 = 4pi * 14 (inch/s) = 14.66 ft/sec
v3 = 14.66 ft/sec(1 mile/5280 ft)( 3600 sec/h)= 9.99 or something about <span>10 mph --- SOLVING FOR B.
</span>I'm sure it helps!
7 0
3 years ago
The position of a 55 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. determine the velocity at t=0.4
NNADVOKAT [17]
The position of the mass is given by (in cm):
x(t)=2 \cos (10 t)
The velocity is the derivative of the position:
v(t) =  \frac{dx(t)}{dt} =-10\cdot 2 \sin (10t)=-20 \sin (10t)
Substituting t=0.40 s, we can find the velocity at this time:
v(0.40 s)= -20 \sin (10 \cdot 0.4)=15 cm/s=15 \cdot 10^{-2}m/s
5 0
3 years ago
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A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical heig
kolezko [41]

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h       conservation of energy

I = 2/5 m R^2     inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

8 0
2 years ago
Why are red stars cooler than blue stars?
asambeis [7]
OK both stars are burning and as they burn they emit electromagnetic radiation (light) and as we move in the light spectrum red comes before blue, so the star that looks red is cooler because as the temperature decreases the colour decreases
6 0
3 years ago
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