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Vlad [161]
2 years ago
12

Mr. Capp runs his own disc golf store every Saturday. The first customer of the day came in and bought

Mathematics
1 answer:
enot [183]2 years ago
8 0

Answer:

a driver costs $19, while a putter costs $12

Step-by-step explanation:

driver = d

putter = p

1d + 2p = 43

3d + 1p = 69

d + 2p = 43. eq 1

3d + p = 69. eq 2

make d the subject of the equation

d = 43 - 2p. eq 3

substitute the value of d in eq 3 in eq 2

3(43 - 2p) + p = 69

129 - 6p + p = 69

collect like terms

129 - 69 = 6p - p

60 = 5p

p = 12

substitute the value of p in eq 3

d = 43 - 2(12)

d = 43 - 24

d = 19

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Find the distance between the two points S (-5,-2) and T (-3,4).
icang [17]

Answer:

d =2 \sqrt{10}

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

S (-5, -2)

T (-3, 4)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-3+5)^2+(4+2)^2}
  2. Add:                              d = \sqrt{(2)^2+(6)^2}
  3. Evaluate:                      d = \sqrt{4+36}
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In circle P with mNRQ = 60°, find the angle measure of minor arc NQ
Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)

Multiply by 2 on both sides.

$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)

$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)

Substitute m∠NRQ = 60°.

$\Rightarrow 2\times 60^\circ=m(ar NQ)

$\Rightarrow 120^\circ=m(ar NQ)

The measure of minor arc NQ is 120°.

8 0
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