The vertices of quadrilateral PQRS are listed.
1 answer:
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9514 1404 393
Answer:
5x +y = 16
Step-by-step explanation:
Given a point and slope, it often works well to start with the point-slope form of the equation for a line:
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
Your point and slope make this ...
y -6 = -5(x -2)
y -6 = -5x +10 . . . . . . eliminate parentheses
5x +y = 16 . . . . . . . . . add 5x+6 to both sides; your standard form equation
