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3 years ago

The graph below is used by company 2 to show the average monthly electric cost based on the electricity provider.

Mathematics

2 answers:

defon3 years ago

7 0

Given the bar graph above, the difference in monthly electric cost appear to be great because of the choice of scale.

In scaling, the narrower the intervals of the axis, the larger the graph and the more highlighted the relative difference between the components of the graph.

Conversely, the wider the the intervals of the axis, the smaller the graph and the less highlighted the relative difference between the components of the graph.

Therefore, to make the difference in monthly electric cost appear not to be as great, we widden the intervals on the y-axis.
i.e. 'The interval on the y-axis could be changed to count by 20s.'

NISA [10]3 years ago

5 0

The answer is A) The scale on the y-axis could be changed to 0–150.

Because the y-axis starts at 95, it makes it seem like the change is huge but it's not actually.

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Y=f(x) = -1x find f(x) when x= 0

Marrrta [24]

Answer:

y = 0

Step-by-step explanation:

If anything is multiplied by a 0 the answer is always going to be 0.

1. Plug 0 into x.

-1(0) = 0

Hope this Helped!!!

~Shane

5 0

3 years ago

Jack is playing a game. When a player wins 3 consecutive games, the player receives 10 bonus points and then the player’s total

svlad2 [7]

Let Jack's current point is $p$

After winning 3 consecutive games, the bonus point is given by
$b(p)=p+10$

The score after 5% = 0.05 increase is
$s(p)= (1+0.05)p=1.05p$

$(s.b)(p)=1.05(p+10)=1.05p+10.5$

3 0

4 years ago

Answer this questions please!!!

Svetradugi [14.3K]

Answer:

sin^2 x

Step-by-step explanation:

By the formula,

sin^2 x + cos^2x = 1

so, 1 - cos^ 2 x = sin ^2

<h2>HOPE IT HELPS U!!!! </h2>

7 0

3 years ago

If an investment account starts with $3,900, and grows with 2.1% interest, compounded annually, how much is the account worth af

zalisa [80]

Answer:

$5327

Step-by-step explanation:

Use the formula for calculating compound interest

A(t)=P(1+r/n)^n⋅t,

where A(t) is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded each year, and t is the time (in years). We are given that P=$3,900, r=0.021, n=1, and t=15. Substituting the values into the formula and using a calculator to evaluate, we find

A(t)=P(1+r/n)^n⋅t = $3,900(1+0.0211)^(15)(1) ≈ $5,326.61

So the final answer is $5,327.

3 0

3 years ago

Factoring trinomials

Tcecarenko [31]

$c^2$ $2c^2 + 13c +21 \\4c^2 + 13(2)c + 42\\(2c + 6)(2c+7)\\(c+3)(2c+7)$

This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying $c^2$ . This is the second line. Then, you could take the square of the $4c^2$ , ant try to create a factor () () that will correspond to the expression in the second line. That is, we want $4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)$

In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have $(2c + 6) (2c +7)$

The last step is divide by the number that we multipy in the first step.

4 0

3 years ago