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ella [17]
3 years ago
9

Kinetic energy during an object falling

Physics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

kinetic \: energy =  \frac{1}{2} m {v}^{2}  \\  m = mass \: of \: the \: object \\ v = velocity \:

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Diamonds Choose one:
Daniel [21]

Answer:

D. are brought from the mantle to the surface in magma that hardens into komatiite.

Explanation:

Diamond :

 It is the hardest form of carbon.The atomic atoms arrange in the cubic crystal structure and this is known as diamond cubic.Another form of the diamond at room temperature is graphite.This is used for making jewelry.This is also used in the cutting process because it has high strength.

Therefore the correct option for the diamond is D.

4 0
3 years ago
(5) A 4 kg. object rests on a flat, horizontal surface with a static
baherus [9]

Answer:

F = 9.81 [N]

Explanation:

To solve this problem we must use Newton's third le which tells us that the sum of forces on a body that remains static must be equal to one resulting from these forces in the opposite direction.

Let's perform a summation of forces on the vertical axis-y to determine the normal force N.

∑F = 0 (axis-y)

N - m*g = 0

where:

m = mass = 4 [kg]

g = gravity acceleration = 9.81 [m/s²]

N - (4*9.81)=0\\N = 39.24 [N]

Now we know that the frictional force can be calculated using the following equation.

f = μ*N

where:

f = friction force [N]

μ = friction coefficient = 0.25

N = normal force = 39.24 [N]

Now replacing:

f = 0.25*39.24\\f = 9.81[N]

Then we perform a sum of forces on the X-axis equal to zero. This sum of forces allows us to determine the minimum force to be able to move the object in a horizontal direction.

∑F = 0 (axis-x)

F-f=0\\F-9.81=0\\F= 9.81[N]

If the coefficient was smaller, a smaller force (F) would be needed to start the movement, this can be easily seen by replacing the value of 0.25, by smaller values, such as 0.1 or 0.05.

If the coefficient were larger, a larger force would be needed.

3 0
3 years ago
If a negatively charged particle is placed inside a uniform electric field the electric force that will act on that particle poi
AysviL [449]

Answer:

opposite direction

Explanation:

An electric field is defined as a physical field which surrounds the electrically charged particles that exerts force on the other particles on the field.

Now when an electron or a negatively charged particle enters a uniform electric field, the electric forces acts on the negatively charged particles and it forces the particle to move in the direction which is opposite to the direction of the field. In an uniform electric field, the field lines are parallel.

6 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY!
BARSIC [14]
<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />

According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is <u>the acceleration of gravity</u>.  

Now, in this case we are on Earth, so the gravity value is 9.8\frac{m}{s^{2}}  

Note the objects experience the acceleration of gravity regardless of their mass.

Nevertheless, on Earth we have air, hence <u>air resistance</u>, so the afirmation <em>"Free fall is a situation in which the only force acting upon an object is gravity" </em>is not completely  true on Earth, unless the following condition is fulfiled:

If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at 9.8\frac{m}{s^{2}} and hit the ground at approximately the same time.  


5 0
4 years ago
A racecar accelerates uniformly from 18.5 mil to 46.1 m/s in 2.47 seconds.
laiz [17]

Answer:

<em>The acceleration of the racecar is</em> \mathbf{11.17~m/s^2}

Explanation:

<u>Uniformly Accelerated Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

\displaystyle a=\frac{v_f-v_o}{t}

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

\displaystyle a=\frac{46.1-18.5}{2.47}

\displaystyle a=\frac{27.6}{2.47}

a = 11.17~m/s^2

The acceleration of the racecar is \mathbf{11.17~m/s^2}

5 0
3 years ago
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