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Artyom0805 [142]
3 years ago
5

A 92-kg skier is sliding down a ski slope that makes an angle of 40 degrees above the horizontal direction. the coefficient of k

inetic friction between the skis and the snow is 0.293. neglecting any air resistance, what is the acceleration of the skier?
a) 5.8 m/s2
b) 4.9 m/s2
c) 9.8 m/s2
d) 4.1 m/s2
e) 2 m/s2
Physics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

d) a = 4.1 m/s²

Explanation:

m = 92 Kg

∅ = 40º

μ = 0.293

a = ?

We can obtain the forces in the direction x' (of motion)

Wx' = W*Sin ∅ = m*g*Sin ∅

Ffriction = μ*N = μ*m*g*Cos ∅

then we use Newton's 2nd Law as follows:

Wx' - Ffriction = m*a

m*g*Sin ∅ - μ*m*g*Cos ∅ = m*a

⇒   a = g*(Sin ∅ - μ*Cos ∅)

⇒   a = (9.81 m/s²)*(Sin 40º - 0.293*Cos 40º)

⇒   a = 4.1038 m/s²

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