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scoundrel [369]

2 years ago

12

Please help: I don't know how to do these problems

1 answer:

antiseptic1488 [7]2 years ago

3 0

d =2.55.68m and t = 11.36s
In my opinion

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Which statement about plant and animal cells is true?

Ivan

Answer:

C. Both use mitochondria to release energy

Explanation:

Plant cells have a cell wall, a large vacuole and chloroplasts but animal cells do not.

4 0

2 years ago

How many galaxies similar in size to the milky way would you expect to find, on average, in cubes of that same size? in order to

pishuonlain [190]

The number of galaxies similar in size to the milky way that one can expect to find in cubes of that same size will be 64.

<h3>What is a milky way?</h3>

It should be noted that milky way simply means a spiral galaxy shaped that contains stars.

Here, the number of galaxies similar in size to the milky way that one can expect to find in cubes of that same size will be 64.

Learn more about milky way on:

brainly.com/question/13956361

3 0

2 years ago

What is one property of a suspension that is different from that of a solution or a colloid?

Step2247 [10]

Answer:

A

Explanation:

If left to rest it will separate.

3 0

2 years ago

A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.

strojnjashka [21]

Answer:

$D=99.4665307m \approx 99.5m$

Explanation:

From the question we are told that

Mass $m=6kg$

Velocity of mass $V_m=16$

Force of Tunnel $F_t=8N$

Length of Tunnel $L_t=1.6$

Height of frictional incline $H_i=2.9$

Angle of inclination $\angle =16 \textdegree$

Acceleration due to gravity $g=9.8m/s^2$

First Frictional surface has a coeﬃcient $\alpha_1 =0.21\ for\ d_c=1$

Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

Generally the initial Kinetic energy is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}(6)(16)^2$

$K.E=768$

Generally the work done by the Tunnel is mathematically given as

$w_t=F_t*d_t$

$w_t=8*1.6$

$w_t=12.8J$

Therefore

$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

$E_t=K.E+E_t\\E_t=768J+12.8J$

$E_t=780.8J$

Generally the energy lost while climbing is mathematically given as

$E_c=mgh$

$E_c=(6)(9.8)(2.9)$

$E_c=170.52J$

Generally the energy lost to friction is mathematically given as

$E_f=\alpha *m*g*cos\textdegree*d_c$

$E_f=0.21*6*9.8*cos16*1$

$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

$E_m=585.48J$

Since

$E_m=\alpha_2*g*m*d$

Therefore

It slide along the second frictional region

$D=\frac{585.46}{0.1*9.81*6}$

$D=99.4665307m \approx 99.5m$

6 0

3 years ago

A lightning flash releases about 1010J of electrical energy. Part A If all this energy is added to 50 kg of water (the amount of

zavuch27 [327]

Answer:

water is in the vapor state,

Explanation:

We must use calorimetry equations to find the final water temperatures. We assume that all energy is transformed into heat

E = Q₁ + $Q_{L}$

Where Q1 is the heat required to bring water from the current temperature to the boiling point

Q₁ = m $c_{e}$ ( $T_{f}$ -T₀)

Q₁ = 50 4180 (100 - 37)

Q₁ = 1.317 10⁷ J

Let's calculate the energy so that all the water changes state

$Q_{L}$ = m L

$Q_{L}$ = 50 2,256 106

$Q_{L}$ = 1,128 10⁸ J

Let's look for the energy needed to convert all the water into steam is

Qt = Q₁ + $Q_{L}$

Qt = 1.317 107 + 11.28 107

Qt = 12,597 10⁷ J

Let's calculate how much energy is left to heat the water vapor

ΔE = E - Qt

ΔE = 10¹⁰ - 12,597 10⁷

ΔE = 1000 107 - 12,597 107

ΔE = 987.4 10⁷ J

With this energy we heat the steam, clear the final temperature

Q = ΔE = m $c_{e}$ ( $T_{f}$ -To)

( $T_{f}$ -T₀) = ΔE / m $c_{e}$

$T_{f}$ = T₀ + ΔE / m $c_{e}$

$T_{f}$ = 100 + 987.4 10⁷ / (50 1970)

$T_{f}$ = 100 + 1,002 10⁵

$T_{f}$ = 1,003 10⁵ ° C

This result indicates that the water is in the vapor state, in realizing at this temperature the water will be dissociated into its hydrogen and oxygen components

4 0

2 years ago