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scoundrel [369]
3 years ago
12

Please help: I don't know how to do these problems

Physics
1 answer:
antiseptic1488 [7]3 years ago
3 0
d =2.55.68m and t = 11.36s
In my opinion
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PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!
gladu [14]

Here given that x is inversely depends of y

so as we increase the value of y so due to inverse dependency it will decrease the value of x

So here we can also say that when x inversely depends on y

so the product of x and y will remain constant here

so here the graph should be like this that if we increase the quantity on x axis then it will decrease the other quantity on y axis

<u><em>So here best appropriate graph must be option A</em></u>

3 0
3 years ago
A shovel is the third class lever​
Nookie1986 [14]

Answer:

Yes

Explanation:

In a third-class lever, the effort force lies between the resistance force and the fulcrum. Some kinds of garden tools are examples of third-class levers. When you use a shovel, for example, you hold one end steady to act as the fulcrum, and you use your other hand to pull up on a load of dirt.

8 0
3 years ago
Under ideal conditions (no atmospheric interference of any kind), if I hit a golf ball at an angle of 25 degrees at an initial s
g100num [7]

Answer:

The required angle is (90-25)° = 65°

Explanation:

The given motion is an example of projectile motion.

Let 'v' be the initial velocity and '∅' be the angle of projection.

Let 't' be the time taken for complete motion.

Let 'g' be the acceleration due to gravity

Taking components of velocity in horizontal(x) and vertical(y) direction.

v_{x} =  v cos(∅)

v_{y} =  v sin(∅)

We know that for a projectile motion,

t =\frac{2vsin(∅)}{g}

Since there is no force acting on the golf ball in horizonal direction.

Total distance(d) covered in horizontal direction is -

d = v_{x}×t = vcos(∅)×\frac{2vsin(∅)}{g} = \frac{v^{2}sin(2∅) }{g}.

If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -

α +β = 90° as-

d = \frac{v^{2}sin(2α) }{g} = \frac{v^{2}sin(2[90-β]) }{g} =\frac{v^{2}sin(180-2β) }{g} = \frac{v^{2}sin(2β) }{g} .

∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.

∴ If α = 25° , then

     β = 90-25 = 65°

∴ The required angle is 65°.

5 0
3 years ago
Read 2 more answers
Astar is 10 light years away from the earth. Suppose it brightens up suddenly today, after how long can we see this change?
Blababa [14]

The phrase "light year" is a <u><em>distance</em></u> ... it's the distance that light travels through vacuum in one year.

When you look at an object located 1 light year away from you, you see it as it was 1 year ago.

If a star located 10 light years away from us suddenly brightens, or dims, or explodes, we see the event <em>10 years later.</em>

7 0
3 years ago
________ reaction time involves selecting a specific and correct response from several choices when presented with several diffe
kobusy [5.1K]
Complex reaction time involves selecting a specific and correct response from several choices when presented with several different stimuli.
Answer: A
8 0
3 years ago
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