Please help: I don't know how to do these problems

Usimov [2.4K]

Answer:heat brings it up then down

Explanation:

4 0

3 years ago

An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a

S_A_V [24]

Answer:

Given:

Thermal Kinetic Energy of an electron, $KE_{t} = \frac{3}{2}k_{b}T$

$k_{b} = 1.38\times 10^{- 23} J/k$ = Boltzmann's constant

Temperature, T = 1800 K

Solution:

Now, to calculate the de-Broglie wavelength of the electron, $\lambda_{e}$ :

$\lambda_{e} = \frac{h}{p_{e}}$

$\lambda_{e} = \frac{h}{m_{e}{v_{e}}$ (1)

where

h = Planck's constant = $6.626\times 10^{- 34}m^{2}kg/s$

$p_{e}$ = momentum of an electron

$v_{e}$ = velocity of an electron

$m_{e} = 9.1\times 10_{- 31} kg$ = mass of electon

Now,

Kinetic energy of an electron = thermal kinetic energy

$\frac{1}{2}m_{e}v_{e}^{2} = \frac{3}{2}k_{b}T$

$}v_{e} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{e}}}$

$}v_{e} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{9.1\times 10_{- 31}}}$

$v_{e} = 2.86\times 10^{5} m/s$ (2)

Using eqn (2) in (1):

$\lambda_{e} = \frac{6.626\times 10^{- 34}}{9.1\times 10_{- 31}\times 2.86\times 10^{5}} = 2.55 nm$

Now, to calculate the de-Broglie wavelength of proton, $\lambda_{e}$ :

$\lambda_{p} = \frac{h}{p_{p}}$

$\lambda_{p} = \frac{h}{m_{p}{v_{p}}$ (3)

where

$m_{p} = 1.6726\times 10_{- 27} kg$ = mass of proton

$v_{p}$ = velocity of an proton

Now,

Kinetic energy of a proton = thermal kinetic energy

$\frac{1}{2}m_{p}v_{p}^{2} = \frac{3}{2}k_{b}T$

$}v_{p} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{p}}}$

$}v_{p} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{1.6726\times 10_{- 27}}}$

$v_{p} = 6.674\times 10^{3} m/s$ (4)

Using eqn (4) in (3):

$\lambda_{p} = \frac{6.626\times 10^{- 34}}{1.6726\times 10_{- 27}\times 6.674\times 10^{3}} = 5.94\times 10^{- 11} m = 0.0594 nm$

7 0

3 years ago

A line graph usually reveals a relationship between which factors

SVEN [57.7K]

Answer:

variables on the horizontal and vertical axis (slope, outliers, +/- correlation, etc)

Explanation:

6 0

3 years ago

According to the definition of mechanical work, pushing on a rock accomplishes no work unless there is

LekaFEV [45]

There must be movement in the same direction as the force put on the object. Hope this helps!

4 0

3 years ago

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PLEASE HELP WILL GIVE BRAINLEST

mart [117]

1. Meiosis has 2 cell divisions but mitosis has only one cell division. Meiosis I is same as mitosis because parent cell produces diploid cells. But the difference between meiosis and mitosis is after the complete process meiosis produces genetically different haploid daughter cells and mitosis produces genetically same diploid daughter cells.

2. The main advantage of the sexual reproduction is It helps to produce offspring which can be well adapted to the environmental conditions due to the genetically differentiations. Hence, there are various types of offspring in the population. But the disadvantage is it requires two parents and it requires more time than asexual reproduction.

3. Advantages of asexual reproduction are it requires only parent, time for the process is relatively low, it produces genetically identical offspring. The main disadvantage is due to the production of genetically identical offspring, the survival rate is low when there is a disaster.

4. The organism can do either sexual reproduction or asexual reproduction to produce offspring. If it is difficult to find a partner to mate, the living being can do asexual reproduction to make offspring in a short period of time. When the organism needs genetically different offspring for survival, they can do sexual reproduction.

7 0

3 years ago

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