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scoundrel [369]
3 years ago
12

Please help: I don't know how to do these problems

Physics
1 answer:
antiseptic1488 [7]3 years ago
3 0
d =2.55.68m and t = 11.36s
In my opinion
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Can someone give me tips for this essay assignment?
garik1379 [7]
Just write a summary don't do the little details and don't explain everythinh
7 0
3 years ago
If sunlight shines straight onto a peacock feather, the feather appears bright blue when viewed from 15° on either side of the i
velikii [3]

Answer:

  d = 1.82 10⁻⁶ m = 1.82 μm

Explanation:

The diffraction phenomenon is explained by a similar equation Young's double slit equation

    d sin θ = n λ

Where d is the spacing between the bars, θ is the angled diffraction, n in an integer representing the order of diffraction and λ is the wavelength of light

Let's calculate

     d = n λ / sin θ

     d = 1 470 10⁻⁹ /sin 15

     d = 1.82 10⁻⁶ m = 1.82 μm

6 0
3 years ago
A 0.350 kg block at -27.5°C is added to 0.217 kg of water at 25.0°C. They come to equilibrium at 16.4°C. What is the specific he
Gekata [30.6K]

The specific heat capacity of the block is 508J/kg^{\circ}C

Explanation:

As the block is placed into the water, heat energy is transferred from the water (which is at higher temperature) to the block (which is at lower temperature), until the block and the water are in thermal equilibrium (= same temperature).

Therefore, we can write:

Q_{water}=Q_{block}

Where

Q_{water}=m_w C_w (T_w-T_{eq}) is the heat energy released by the water, where

m_w = 0.217 kg is the mass of the water

C_w = 4186 J/kg^{\circ}C is the water heat specific capacity

T_w = 25.0^{\circ} is the initial temperature of the water

T_{eq}=16.4^{\circ} is the temperature at equilibrium

Substituting,

Q_{water}=(0.217)(4186)(25.0-16.4)=7812 J

Now we can write the heat energy absorbed by the block as

Q_{block}=m_b C_b(T_{eq}-T_b)

where

m_b=0.350 kg is the mass of the block

C_b is the specific heat capacity of the block

T_b = -27.5^{\circ} is the initial temperature of the block

And solving for C_b,

C_b=\frac{Q_{block}}{m_b(T_{eq}-T_b)}=\frac{7812}{(0.350)(16.4-(-27.5))}=508J/kg^{\circ}C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

6 0
3 years ago
What does the law of conservation of energy state?
VikaD [51]

The total amount of energy remains constant in an isolated system. It implies that energy can neither be created nor destroyed, but can be change from one form to another.

6 0
3 years ago
Is hot asphalt that is poured into the ground and cools a physical or chemical change?
Gala2k [10]
Physical change
Because it's changed by heat
5 0
4 years ago
Read 2 more answers
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