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Artemon [7]
3 years ago
6

Which factor affects the amount of runoff that occurs in an area?

Physics
1 answer:
jarptica [38.1K]3 years ago
4 0

ion:

h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = x a a z U g E K u V A

this is the video that explains it

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3. Do Newton's Laws of Motion apply to a Water Spout? If so, how?
PSYCHO15rus [73]
Yes it’s spills out becasue bucket
6 0
3 years ago
Physics - Electricity and Magnetism
Orlov [11]

Answer:

<h2>480</h2>

Explanation:

<h2>R=120÷0.25</h2><h2>R=480 ohms </h2>

because the unit for resistance is in ohms

4 0
2 years ago
2. Which statement is correct about the Krebs cycle?
IRINA_888 [86]

The correct option is


a. Acetyl-CoA combines with a pyruvic acid to make glucose in the Krebs cycle.


Explanation:

The Krebs citric acid cycle happens within the mitochondrial matrix and generates a pool of energy (ATP, NADH, and FADH2) from the oxidization of pyruvate, the tip product of metabolism. Pyruvate is transported into the mitochondria and loses dioxide to make acetyl-CoA, a 2-carbon molecule.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (60pts)
mr Goodwill [35]
The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.
So since the boat has a lower density than the water, it will float.
So the answer is choice B
3 0
3 years ago
A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
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